Bunuel wrote:
On the line above, if AB < BC < CD < DE, which of the following must be true?
(A) AC < CD
(B) AC < CE
(C) AD < CE
(D) AD < DE
(E) BD < DE
Attachment:
2017-07-12_1253.png
Given AB<BC<CD<DE
Please note that all the values which AB, BC, CD or DE take will be positive. Lets assume
AB = a
BC=a+x
CD=a+x+y
DE=a+x+y+z
All a,x,y,z are positive
(A) AC < CD => AB+BC<CD => a+a+x<a+x+y (a could be greater than y) Nope
(B) AC < CE => AB+BC<CD+DE => a+a+x<a+x+y+a+x+y+z => 0<y+x+y+z and since x,y,z is positive..this is our answer
(C) AD < CE => AB+BC+CD<CD+DE => AB+BC<DE => a+a+x<a+x+y+z (a could be greater than y+z) Nope
(D) AD < DE => AB+BC+CD < DE => a+a+x+a+x+y<a+x+y+z (2a+x could be larger than z) Nope
(E) BD < DE => BC+CD<DE => a+x+a+x+y<a+x+y+z (a+x could be larger than z) Nope
Hence B
We can also use smart numbers like a=6, x=2, y=3, z=4
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