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Re: On the number line, if w > x, y is the midpoint between w and z, and x [#permalink]
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Nevernevergiveup wrote:
On the number line, if \(w > x\), \(y\) is the midpoint between \(w\) and \(z\), and \(x\) is twice as far from \(z\) as it is from \(w\), then \(\frac{(w – y)}{(z – x)}\) could equal which of the following?

A) -2

B) \(-\frac{1}{4}\)

C) 0

D) \(\frac{1}{4}\)

E) \(\frac{3}{2}\)


Based on the information given, you need to visualize a couple of possible scenarios to rule out obvious outliers from the given options.

You are given w>x and that |x-z| = 2 |x-w| ---> a possible scenario on the numberline is

-----0---z----y----x---w.

This scenario shows that the value of z-y < 0 while w-y > 0 ---> (w-y)/(z-x) < 0 ---> eliminate D and E.

Now to C), you can clearly see that you can get (w-y)/(z-x) = 0 by having w=y and this is not possible as it is given that y is midway between w and z and hence y \(\neq\) w

Thus you now have 2 options remaining, A and B.

Take A) now. Lets assume (w-y)/(z-x) =2 ---> w-y = 2(z-x) and do substitute y = (w+z)/2 to get, w/2 - z/2 = 2z-2x...(1)

Additionally, from the above scenario, you know that x-z = 2/3 * (w-z) ....(2)

Thus from substituting value of x from (2) to (1), you end up getting on rearranging the terms, w=z. This is not possible as this will make 'y' = w= z. Thus A ) is not possible, leaving B as the only possible scenario.

Hence B is the correct answer.

Hope this helps.
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On the number line, if w > x, y is the midpoint between w and z, and x [#permalink]
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Nevernevergiveup wrote:
On the number line, if \(w > x\), \(y\) is the midpoint between \(w\) and \(z\), and \(x\) is twice as far from \(z\) as it is from \(w\), then \(\frac{(w – y)}{(z – x)}\) could equal which of the following?

A) -2

B) \(-\frac{1}{4}\)

C) 0

D) \(\frac{1}{4}\)

E) \(\frac{3}{2}\)


Just insert these numbers in the expression \(\frac{(w – y)}{(z – x)}\) and you'll get the answer (B)
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Re: On the number line, if w > x, y is the midpoint between w and z, and x [#permalink]
I get that the answer is B

Using BrainLab diagram from above (it seems I can't post URLs unless I have 5 posts),


Aren't w, x, y, z points on the line segment, so (w–y) would be the distance between w and y (non-negative)?

Thus \(\frac{(w–y)}{z-x}\) should be :

2/8 = 1/4 ?
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On the number line, if w > x, y is the midpoint between w and z, and x [#permalink]
Nevernevergiveup wrote:
On the number line, if \(w > x\), \(y\) is the midpoint between \(w\) and \(z\), and \(x\) is twice as far from \(z\) as it is from \(w\), then \(\frac{(w – y)}{(z – x)}\) could equal which of the following?

A) -2

B) \(-\frac{1}{4}\)

C) 0

D) \(\frac{1}{4}\)

E) \(\frac{3}{2}\)



x-------------------------------w

x-------------------------------w---------------y-----------------z
or
z------------------------------------------------y-----------------x---------------------------------w

(w-y)/(z-x) = -1/4

(w-y)/(z-x) = 3/(-4)=-3/4

IMO B
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Re: On the number line, if w > x, y is the midpoint between w and z, and x [#permalink]
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Re: On the number line, if w > x, y is the midpoint between w and z, and x [#permalink]
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