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# On the number line shown, is zero halfway between r and s

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Senior Manager
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On the number line shown, is zero halfway between r and s [#permalink]

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06 Apr 2009, 09:43
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Question Stats:

33% (00:00) correct 67% (00:00) wrong based on 8 sessions

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On the number line shown, is zero halfway between r and s

<-----------------r---------s----t----------->

1)s is to the right of zero
2)The distance between t and r is the same as the distance between t and -s

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Manager
Joined: 19 Oct 2008
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06 Apr 2009, 13:02
B.

1) NS since we don't know the position of r.
2) Pick numbers for r,s and t, the only way it can be true if r=-s. Therfore, sufficient

r=-2
t=12
distance between r and t =14
then s=2
and zero is between s and r.

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GMAT Tutor
Joined: 24 Jun 2008
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06 Apr 2009, 16:28
Accountant wrote:
B.
2) Pick numbers for r,s and t, the only way it can be true if r=-s. Therfore, sufficient

r=-2
t=12
distance between r and t =14
then s=2
and zero is between s and r.

No, Statement 2 is insufficient here. You could have, for example:

t = -1
s = -3
r = -5

Then zero is not halfway between r and s. With statement 1 you can rule out this type of possibility, however.
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Senior Manager
Joined: 01 Mar 2009
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06 Apr 2009, 16:37
IanStewart wrote:
Accountant wrote:
B.
2) Pick numbers for r,s and t, the only way it can be true if r=-s. Therfore, sufficient

r=-2
t=12
distance between r and t =14
then s=2
and zero is between s and r.

No, Statement 2 is insufficient here. You could have, for example:

t = -1
s = -3
r = -5

Then zero is not halfway between r and s. With statement 1 you can rule out this type of possibility, however.

I fell into the trap as well. If you just put 0 to the right of T on the number line, the negative value for T becomes so evident.

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Senior Manager
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06 Apr 2009, 18:44
When you combine both the statements could r be negative?

Meaning, if s is to the right of zero, then r could possibly be on the left(negative) or right (positive) of zero, correct?

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Manager
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06 Apr 2009, 20:23
IMO C.

stmnt 1 - insuffic.
stmnt 2 - insuffic.

Combining them shows that -s=r, so => 0 is between s and -s(r).
Sufficient.

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Re: Number line   [#permalink] 06 Apr 2009, 20:23
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