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Bunuel
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Lets assume 100 Batteries are manufactured.
1/5(100) = 20 are defective.
1/4(100) = 25 are rejected
1/10(100-20) = 8 Rejected by mistake.
75 Non rejected and sold.
So out of 25 batteries, 8 are rejected by mistake => 25-8 =17.
20 were defective and 17 are already rejected, but 3 leaked to non-rejected lot.
(3/75)*100 = 4%

Answer is A.
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took the total number as 200 and solved it in a matrix fashion .that way i found it easy
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Bunuel

Tough and Tricky questions: Overlapping Sets.



One-fifth of the batteries produced by an upstart factory are defective and one-quarter of all batteries produced are rejected by the quality control technician. If one-tenth of the nondefective batteries are rejected by mistake, and if all the batteries not rejected are sold, then what percent of the batteries sold by the factory are defective?

A) 4%
B) 5%
C) 6%
D) 8%
E) 12%

We can let the total number of batteries produced = 100.

Thus, 1/5(100) = 20 batteries are defective and thus 80 batteries are not defective.

Also, 1/4(100) = 25 are rejected and thus 75 batteries are not rejected and are sold.

1/10(80) = 8 non-defective batteries are rejected by mistake and thus 72 non-defective batteries are sold. However, since there are a total of 75 batteries sold, among them, thus must be 75 - 72 = 3 defective batteries. Therefore, the percent of the batteries sold that are defective is:

3/75 = 1/25 = 4%

Answer: A
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