TheKingInTheNorth
hi ,
can anyone provide a solution using variable approach
Let x be the amount of grass work,
Speed of a person per hour = x/4
Now since the speed of the whole process when two people working will be the sum of the net speed of the individuals in that work, and that it is also given that the time it took to complete the whole process was 3 hours,
Speed of the process = x/3
and
net Speed of person 1 during that time + net speed of person 2 during that time = Speed of the whole process
x/4 + net speed of person 2 = x/3
net speed of person 2 = x/12
Now let t1 be the duration of time in those 3 hours that he worked and t2 be the duration of time wherein he did not work i.e the lag time.
Average/net speed = Total work done by person 2 / Total time
hence, x/12 = (x/4 * t1)/3
which gives t1 = 1 hour
and since t1 + t2 = 3 hours
t2, or lag time, = 3-1 = 2 hours