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27 Jan 2021, 14:49
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One ticket is selected from 100 tickets numbered 00, 01, 02, 03, ..., 98, 99. If X is defined as sum of digits and Y as product of the digits, what is the probability that X = 9, given Y = 0?
A. 10/19
B. 2/19
C. 1/10
D. 2/100
E. 1/100
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
A. 10/19
B. 2/19
C. 1/10
D. 2/100
E. 1/100
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
Bunuel
Y = 0 for 00, 10, 20, 30, 40, 50, 60, 70, 80, 90 and 01, 02, 03, 04, 05, 06, 07, 08, 09
Total 19 cases.
X = 9 only for 2 cases i.e. 09 and 90.
P(X=9, Y=0) = 2/19 = 2/19.
Answer B.
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28 Jan 2021, 00:26
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X = 9, for 10 cases
Y = 0 for 20 cases
Probability that X = 9, given Y = 0 =>\(\frac{10}{100}\)*\(\frac{20}{100}\) = \(\frac{2}{100}\)
IMO Option D
Y = 0 for 20 cases
Probability that X = 9, given Y = 0 =>\(\frac{10}{100}\)*\(\frac{20}{100}\) = \(\frac{2}{100}\)
IMO Option D
