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# Originally 20 people had signed up to rent a house for the summer in L

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Math Expert
Joined: 02 Sep 2009
Posts: 42338

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Originally 20 people had signed up to rent a house for the summer in L [#permalink]

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10 Sep 2017, 05:48
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Difficulty:

35% (medium)

Question Stats:

71% (01:29) correct 29% (00:24) wrong based on 28 sessions

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Originally 20 people had signed up to rent a house for the summer in Long Island, with each person contributing equally to the total cost of c dollars. If 10 people had to drop out, but two more signed up, how much more would each person have to pay?

A. c/30

B. c/12

C. c/8

D. 11c/24

E. 2c/25
[Reveal] Spoiler: OA

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Kudos [?]: 133122 [0], given: 12415

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Joined: 26 Feb 2016
Posts: 1624

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Location: India
WE: Sales (Retail)
Originally 20 people had signed up to rent a house for the summer in L [#permalink]

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10 Sep 2017, 06:21
IMO, the best way to find the solution to this problem, is by assigning a value for c

Since 20 people and later 12 people share this cost, lets take a number that is easy to work with(240$) So initially, each of the people had contributed $$(\frac{240}{20} = 12)$$ After 10 people quit and 2 new people joined, there are $$20 - 10 + 2 = 12$$ people. So, the individual contribution is $$(\frac{240}{12} = 20)$$ and it goes up $$8$$ Substituting the value of c=240$, we get the cost going up(8\$) using Option A($$\frac{c}{30}$$)
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Kudos [?]: 696 [0], given: 17

Manager
Joined: 02 Nov 2015
Posts: 176

Kudos [?]: 26 [0], given: 121

GMAT 1: 640 Q49 V29
Re: Originally 20 people had signed up to rent a house for the summer in L [#permalink]

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10 Sep 2017, 07:34
Per head cost initially is C/20.
After 10 persons leave and 2 Join then there are 12 persons in total.

So the extra amount to be paid by each individual is
C/12 - C/20
Which gives C/30.

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Kudos [?]: 26 [0], given: 121

Senior Manager
Joined: 02 Jul 2017
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Kudos [?]: 85 [0], given: 65

GMAT 1: 730 Q50 V38
Re: Originally 20 people had signed up to rent a house for the summer in L [#permalink]

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10 Sep 2017, 10:02
Let initially each pay amount x
so 20* x= c => x= c/20 <= money paid by each person

Now 10 people dropped out and 2 got added. So not number of person =12

So assume each have to pay y amount now. Total amount remain constant
=> 12 * y =c => y=c/12 <= amount each person will be paying now.

So difference in Amount paid = y - x
= c/12 - c/20 = 2c/60 = c/30

Kudos [?]: 85 [0], given: 65

Re: Originally 20 people had signed up to rent a house for the summer in L   [#permalink] 10 Sep 2017, 10:02
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