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Out of 5.5 billion bacteria grown for an experiment, 1 in 75 million
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16 Jun 2018, 00:20
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74% (01:19) correct 26% (01:18) wrong based on 86 sessions
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Out of 5.5 billion bacteria grown for an experiment, 1 in 75 million has a particular mutation. Approximately how many of the bacteria have the mutation?
Re: Out of 5.5 billion bacteria grown for an experiment, 1 in 75 million
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16 Jun 2018, 01:44
Bunuel wrote:
Out of 5.5 billion bacteria grown for an experiment, 1 in 75 million has a particular mutation. Approximately how many of the bacteria have the mutation?
(A) 7 (B) 73 (C) 733 (D) 7,333 (E) 73,333
we just need to find how many 75 million (1million = \(10^6\)) make 5.5 billion (1billion = \(10^9\))
\(\frac{5.5*10^9}{75*10^6}\) ~73 Ans B
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Re: Out of 5.5 billion of bacteria grown for an experiment, 1 in 75 millio
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05 Jul 2018, 08:35
Bunuel wrote:
Out of 5.5 billion of bacteria grown for an experiment, 1 in 75 million has a particular mutation. Approximately how many of these bacteria have the mutation?
(A) 7 (B) 73 (C) 733 (D) 7,333 (E) 73,333
1 billion = 1000 million 5.5 billion = 5500 million \(\frac{5500}{75}\) = 73.333
Re: Out of 5.5 billion of bacteria grown for an experiment, 1 in 75 millio
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05 Jul 2018, 11:04
Bunuel wrote:
Out of 5.5 billion of bacteria grown for an experiment, 1 in 75 million has a particular mutation. Approximately how many of these bacteria have the mutation?
(A) 7 (B) 73 (C) 733 (D) 7,333 (E) 73,333
\(75\) million has \(1\) bacterial mutation \(1\) million has \(\frac{1}{75}\) bacterial mutations \(5500\) million has \(\frac{1}{75}*5500\) bacteria \(~\) \(73\) bacterial mutations , Answer must be (B) _________________
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Re: Out of 5.5 billion of bacteria grown for an experiment, 1 in 75 millio
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05 Jul 2018, 12:47
Bunuel wrote:
Out of 5.5 billion of bacteria grown for an experiment, 1 in 75 million has a particular mutation. Approximately how many of these bacteria have the mutation?
(A) 7 (B) 73 (C) 733 (D) 7,333 (E) 73,333
Total no of bacteria having mutation=Total no of bacteria* rate of mutation=5.5 billion*\(\frac{1 nos}{75 million}\)=\(\frac{5.5*1000 million}{75million}\)=73(Approx.) Ans. (B)
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Re: Out of 5.5 billion of bacteria grown for an experiment, 1 in 75 millio
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06 Jul 2018, 02:39
Solution
Given:
• Total number of bacteria grown for an experiment = 5.5 billion • 1 in every 75 million bacteria has a particular mutation
To find:
• Approximately, how many of these 5.5 billion bacteria has the mutation
Approach and Working:
• In 75 million bacteria, there is 1 bacteria with the mutation • In 5.5 billion bacteria grown for the experiment, number of bacteria which have the mutation = 1 * 5.5 billion/75 million = (5.5 * \(10^9\))/(75 * \(10^6\)) = 5500/75 • The value is greater than 10 and less than 100
Re: Out of 5.5 billion of bacteria grown for an experiment, 1 in 75 millio
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07 Jul 2018, 03:50
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Bunuel wrote:
Out of 5.5 billion of bacteria grown for an experiment, 1 in 75 million has a particular mutation. Approximately how many of these bacteria have the mutation?
Re: Out of 5.5 billion bacteria grown for an experiment, 1 in 75 million
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07 Jul 2018, 07:42
NandishSS wrote:
Bunuel wrote:
Out of 5.5 billion of bacteria grown for an experiment, 1 in 75 million has a particular mutation. Approximately how many of these bacteria have the mutation?
Re: Out of 5.5 billion bacteria grown for an experiment, 1 in 75 million
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07 Jul 2018, 18:26
Bunuel wrote:
Out of 5.5 billion bacteria grown for an experiment, 1 in 75 million has a particular mutation. Approximately how many of the bacteria have the mutation?
(A) 7 (B) 73 (C) 733 (D) 7,333 (E) 73,333
We can create the proportion:
5,500,000,000/n = 75,000,000/1
n = 5,500,000,000/75,000,000 = 5500/75 = about 73
Answer: B
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Re: Out of 5.5 billion bacteria grown for an experiment, 1 in 75 million
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07 Jul 2018, 23:34
\(2^0\) in 75 million \(2^1\) in 150 million (number of bacteria with a mutation doubles every time the sample is doubled i.e 75-150-300-..) \(2^2\) in 300 million \(2^3\) in 600 million \(2^4\) in 1200 million \(2^5\) in 2400 million \(2^6\) in 4800 million; \(2^6 = 64\) \(2^7\) in 9600 million;\(2^7 = 128\)
An option between 64 and 128. Answer is B, 73.
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Re: Out of 5.5 billion bacteria grown for an experiment, 1 in 75 million &nbs
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07 Jul 2018, 23:34
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74% (01:19) correct 
