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13 Nov 2023, 08:42
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(I): \(17000*I\)
(II): \(\frac{100+B}{100+m}*I\)
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
65% (03:26) correct
35%
(03:16)
wrong
based on 263
sessions
History
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Not Attempted Yet
Over a seven-year period, from 2002 to 2009, the number of babies born to married couples increased despite a decrease in marriages from 17,000 marriages in 2002.
In the given expression, B and M represent the percent change in the babies and marriages, respectively. I represents the number of babies per married couple in 2002. The percent change in a quantity is calculated by the formula:
\((\frac{X_{new}-X_{old}}{X_{old}})*100\)
In the table below select for (I) The expression that represents the number of babies born in 2002 and (II) The expression of the number of babies born per family in 2009. Select one value in each column.
In the given expression, B and M represent the percent change in the babies and marriages, respectively. I represents the number of babies per married couple in 2002. The percent change in a quantity is calculated by the formula:
\((\frac{X_{new}-X_{old}}{X_{old}})*100\)
In the table below select for (I) The expression that represents the number of babies born in 2002 and (II) The expression of the number of babies born per family in 2009. Select one value in each column.
| (I) | (II) | |
| \(\frac{17000}{I}\) | ||
| \(17000*I\) | ||
| \(\frac{100+B}{100+m}*I\) | ||
| \(\frac{100-B}{100+m}*I\) | ||
| \(\frac{100+m}{100+B}*I\) | ||
| \(\frac{100+m}{100-B}*I\) |
ShowHide Answer
Official Answer
(I): \(17000*I\)
(II): \(\frac{100+B}{100+m}*I\)
14 Nov 2023, 00:09
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In the table below select for :-
(I) The expression that represents the number of babies born in 2002
Marriages in 2002 = 17,000
'I' represents babies born per married couple
So, the number of babies born in 2002 = 17000 * I
(II) The expression of the number of babies born per family in 2009. Select one value in each column..
Change in babies born (%) = B (from 2002 to 2009)
Change in familes, or marriages (%) = m (from 2002 to 2009)
Since, 'I' represents babies born per married couple
I' (ie, number of babies born per family in 2009) = [ (1 + B/100) / (1+m/100) ] * I
= [(100+B)/(100+m)] * I
(I) The expression that represents the number of babies born in 2002
Marriages in 2002 = 17,000
'I' represents babies born per married couple
So, the number of babies born in 2002 = 17000 * I
(II) The expression of the number of babies born per family in 2009. Select one value in each column..
Change in babies born (%) = B (from 2002 to 2009)
Change in familes, or marriages (%) = m (from 2002 to 2009)
Since, 'I' represents babies born per married couple
I' (ie, number of babies born per family in 2009) = [ (1 + B/100) / (1+m/100) ] * I
= [(100+B)/(100+m)] * I
19 Nov 2023, 06:26
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Hello, can someone help me understand how answer to q1 is 17000/I ? Thank you
