What is the remainder when 1044*1047*1050*1053 is divided by

Because you reduced you fraction by 3. That's the reason you are getting 10. Multiply 10 by 3 and you will get correct remainder 30.
If one reduce fraction by some factor to simplify the calculation then one must not forget to multiply answer by same factor in the end.

Answer should be 3. Here is my analysis:

Since all the numbers in the numerator are divisible by 3, the fraction can be reduced to a number with a denominator 11. The remainder should always be less than the divisor. So dividing a number with 11 should leave a remainder less than 11. Looking at the answer choices 3 is the only one that is less than 11.

I tried computing in a calculator (( 1044 * 1047 * 1050 * 1053) + 3) / 33 did not leave any remainder.

Please someone update the OA. It is (A)

Bunuel, Is it the correct approach?

1044*1047*1050*1053 = n*(n + 3)*(n + 6)*(n + 9)

3*6*9 = 162

162/33, remainder = 30

Just a comment on your logic :
If you are saying :
"I tried computing in a calculator (( 1044 * 1047 * 1050 * 1053) + 3) / 33 did not leave any remainder. "
than here remainder will be 33-3=30 .. not 3...

example.... 16/10 = 1 quotient and 6 remainder....
in your terms : (16+4)/10 does not leave a remainder so 16/10 doesn't have a remainder of 4.. instead remainder is 10-4 =6

so if on calculator you see after adding 3.. number gets properly divided means original remainder is 33-3 ie 30. which is the correct answer.

Hope m clear.

What is the remainder when 30 is divided by 4?

One approach:
1. Break the dividend 30 into factors: 30 = 5*6
2. Divide the divisor 4 into each factor: 5/4 = 1 R1, 6/4 = 1 R2
3. Multiple the resulting remainders: 1*2 = 2

Step 3 indicates that 30 divided by 4 will yield a remainder of 2.
This approach can be applied to any problem that asks for the remainder when a large integer is divided by a divisor.
Repeat the 3 steps until the value yielded by Step 3 is less than the divisor.



Since 1044 has a digit sum that is a multiple of 3 (1+0+4+4=9), 1044 is divisible by 3:
1044 = 3*348
Since 1047 is 3 more than 1044, 1047 = 3*348 + 3 = 3(348+1) = 3*349
By extension:
1050 = 3*350
1053 = 3*351
Thus:
1044*1047*1050*1053 = (3*348)(3*349)(3*350)(3*351) = 81*348*349*350*351

Dividing 33 into each of the five factors in blue and multiplying the resulting remainders, we get:
15*18*19*20*21

18*20 = 360
19*21 = (20-1)(20+1) = 20²-1² = 400-1 = 399
Thus:
15*18*19*20*21 = 15*360*399

Dividing 33 into each of the 3 factors in red and multiplying the resulting remainders, we get:
15*30*3

15*30*3 = 1350
Dividing 33 into 1350, we get:
40 R30
The value in green is less than the divisor (33) and thus is the desired remainder.

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