vshaunak@gmail.com wrote:
What is the remainder when 1044 * 1047 * 1050 * 1053 is divided by 33?
A. 3
B. 27
C. 30
D. 21
E. 18
Can somebody suggest a trick to solve this question.
Hi,
Math Experts....need help on this one....
We need to find the remainder in the above case. I started by finding whether any term is divisible by 33 and found the nearest multiple to be 1056 and changed the question to
(1056-12)*(1056-9)*(1056-6)*(1056-3)/33 which can be further reduced to
(-12)(-9)(-6)(-3)/ 33
On simplifying further we get -------> -12*-9*-6*-1/11-------> 648/11 ---Remainder 10.....its not even in the answers choices...
please suggest what's wrong with my approach
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