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They might be wrong in this case coz I don't see any trap in this question as of now

Given |q| < 4, q must lie between −4 and 4, so q − 10 lies between −14 and −6.
The inequality 2x > q − 10 will be satisfied for some allowed value of q only if 2x is greater than −14.
This requires x > −7.
So x = −7 cannot satisfy the condition, but all other options are greater than −7 and can work for some value of q.
Dream009
This is experts global answer key - so it has to be correct

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2x > q - 10
If we plug in x = -7
-14 > q - 10
-4 > q
|q| < 4, so q can take all the values ranging from -3 to 3
-4 > q can’t be satisfied. Answer should be (A) -7

Let’s check the given answer (E) -3
-6 > q - 10
4 > q
q can take values ranging from -3 to 3 to satisfy this condition.
The answer key is wrong.
Correct answer should be (A) -7
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Edited the OA from E to A. Thank you all!
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|q|<4
=> -4<q<4
=> -14<q-10<-6
=> (-14/2)<(q-10)/2<(-6/2)
=> -7<(q-10)/2<-3

Lets call the quantity q(-10)/2 as p
given 2x > q-10
=> x > (q-10)/2
=> x > p

p can take the values (-7,-3) and since x is greater than p
therefore x can not take the value -7
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I approached this by checking the smallest possible value q can take.

Given:

2x > q − 10
and |q| < 4

Since |q| < 4, q cannot be −4, but it can be very close to −4.
To keep it simple, I checked with q = −3.

Then:

2x > −3 − 10
2x > −13
x > −6.5

So x cannot be −7.

The other choices can work with suitable q values, but −7 is always too small.

Answer: (A) −7

I found it quicker to test the boundary value of q instead of trying to rearrange everything algebraically.

— Rajdeep
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|q| < 4
So, -4 < q < 4

2x > q - 10
=> q < 2x + 10 ----(1)
we know that , -4 < q. ----(2)

using (1) + (2)
-4 < 2x + 10
=> 2x > -14
=> x > -7

Ans (A)

ExpertsGlobal5
If 2x > q – 10 and |q| < 4, which of the following cannot be a value of x ?

A. -7
B. -6
C. -5
D. -4
E. -3



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ExpertsGlobal5
If 2x > q – 10 and |q| < 4, which of the following cannot be a value of x ?

A. -7
B. -6
C. -5
D. -4
E. -3

A is the correct answer choice.

Video explanation:

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Why not -3 (E)??
The range for (q-10)/2 is:
-7< (q-10)/2 < -3

If -7 cannot be the answer, so cant -3.
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If 2x > q – 10 and |q| < 4, which of the following cannot be a value of x ?

A. -7
B. -6
C. -5
D. -4
E. -3

Since |q| < 4, we have:

-4 < q < 4

Subtract 10:

-14 < q - 10 < -6

We need:

2x > q - 10

Check x = -7:

2x = -14

But q - 10 is always greater than -14 ( -14 < q - 10 < -6), so x cannot be -7.

Thus, x cannot be -7.

Answer: A.
MakB
Why not -3 (E)??
The range for (q-10)/2 is:
-7< (q-10)/2 < -3

If -7 cannot be the answer, so cant -3.

We have:

-14 < q - 10 < -6

2x > q - 10

So x can be -3 for example, if q = 0.
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