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mikemcgarry
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jlgdr
Not really a 700 question.
Not really a Number Property question, this should be tagged as a Word Problem

Integer constraints are commonly tested on the GMAT

This problem is meant to deal with exactly that

I suggest always simplifying first

3x + 8y = 22

And then x = 22 - 8y / 3

Only 2 works here

Cheers!
J :)
Dear jlgdr,
By your statement "Only 2 works here", do you mean statement #2? In other words, do you mean to imply that (B) is the answer? If not, it's not clear to me what you think the answer is. Furthermore, I would argue that introducing algebra into this problem doesn't necessarily facilitate the solution, and for some students, may confuse them.
Mike :-)
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anupam87
Peter went to the store to buy paint. Small cans cost $30 and larger cans cost $80. How many small cans of paint did he buy?

Statement #1: Peter spent $220 on paint.

Statement #2: Peter bought four cans of paint in total.

Hi

Firstly I am sure this Q must have been discussed earlier too.

Let's see the statements..
I. It gives us equation 30s+80b=220...
ONLY possibility is s=b=2
Sufficient

II. 4 cans can be any combination..
All 4 big. All 4 small. 1&3 etc
Insufficient

A
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(A)
Statement 1 - total spending 220$
We know that number of cans will be a natural number.
Let x be number of small cans and y be number of large cans
If y=1 then 30x=140 => no solution
If y=2 then 30x=60=> x=2
Then y cannot be 3 otherwise sum will be greater than 220.
Statement 1 is sufficient.

Statement 2 : Total 4 cans
Possible cases
(0,4)
(1,3)
(2,2)
(3,1)
(4,0)

Only statement 1 is sufficient
(A)
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chetan2u

Quote:
Let's see the statements..
I. It gives us equation 30s+80b=220...
ONLY possibility is s=b=2
Sufficient

The moment I see two variables I immediately concluded that I need a second linear equation.
How to avoid this trap?
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adkikani
chetan2u

Quote:
Let's see the statements..
I. It gives us equation 30s+80b=220...
ONLY possibility is s=b=2
Sufficient

The moment I see two variables I immediately concluded that I need a second linear equation.
How to avoid this trap?

Generally such kind of linear equations (ax + by = c) have infinitely many solutions for x and y, and we cannot get single numerical values for the variables. But, here in 30x + 80y = 220, x and y must represent the # of cans, so they must be non-negative integers and in this case 30x + 80y = 220 is no longer simple linear equation, it's a Diophantine equation (equations whose solutions must be integers only) and for such kind on equations there might be only one combination of x and y possible to satisfy it. When you encounter such kind of problems you must always check by trial and error whether it's the case.

For more, check C-Trap Question Collection from our Special Questions's Directory.
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