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17 Mar 2011, 10:26
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67% (00:52) correct
33%
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wrong
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The number of antelope in a certain herd increases every yr at a constant rate .If there are 500 antelopes in herd today,how many yrs will it take for the number to double?
1.10 yrs from now,there will be more than 10 times the current no of antelope in the herd.
2.If the herd were to grow in number at twice the current rate,there would be 980 antelope in the group in two yrs.
1.10 yrs from now,there will be more than 10 times the current no of antelope in the herd.
2.If the herd were to grow in number at twice the current rate,there would be 980 antelope in the group in two yrs.
Archived Topic
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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17 Mar 2011, 10:53
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AnkitK
Number of antelopes now be "A"
A=500
Say after t years, it will double
1000=500(1+r)^t
(1+r)^t = 2
What is t?
1.10 yrs from now,there will be more than 10 times the current no of antelope in the herd.
t=10
500(1+r)^10 > 5000
(1+r)^10 > 10
(1+r) > (10)^(1/9)
r> (10)^(1/9) - 1
Don't have to calculate: (10)^(1/9) - 1.
Whatever may be the value; since the r is more than a value. The exact rate is not know.
r could be any number greater than [(10)^(1/9) - 1].
Not Sufficient.
2.If the herd were to grow in number at twice the current rate,there would be 980 antelope in the group in two yrs.
980=500(1+2r)^2
An exact value of r can be calculated from this expression.
Then; we will just have to substitute r into the expression
(1+r)^t = 2
And we will have t.
Sufficient.
Ans: "B"
If we were to calculate just for the sake of it;
980=500(1+2r)^2
(1+2r)^2 = 1.96
1+2r = 1.4
2r = 0.4
r = 0.2
Substitute this value of r;
(1+r)^t = 2
(1+0.2)^t = 2
(1.2)^t = 2
I see that t is a value more than 3 years and less than 4 years.
19 Mar 2011, 03:58
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Total after n years = 500 + nk
n = # of years
k = rate of increase
So the question is basically when is -> 500 + nk = 1000
or for which n, nk = 500
500 + 10k > 10*500
=> 10k > 9*500
=> k > 450
(1) is insufficient because if k is 450, then it will take more than 1 year, if K 500, then n = 1.
980 = 500 + 2*k
=> k = 480/2 = 240
which is sufficient to predict, hence answer is B.
n = # of years
k = rate of increase
So the question is basically when is -> 500 + nk = 1000
or for which n, nk = 500
500 + 10k > 10*500
=> 10k > 9*500
=> k > 450
(1) is insufficient because if k is 450, then it will take more than 1 year, if K 500, then n = 1.
980 = 500 + 2*k
=> k = 480/2 = 240
which is sufficient to predict, hence answer is B.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
