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Bunuel
Positive integers a, b and c are all less than 10. If the sum of all the distinguishable three digit numbers that can be formed by juxtaposing these integers is 1332, is a = b?

(1) c = 3
(2) a = 2


Let us see the case when a=b.
1) a=b=c,
then the sum would be the number itself as only one number can be formed.
2) a=b and c is different
Total 3-digit number that can be formed is 3!/2!=3. aac, aca, caa
When you add them each digit gets added once => (100a+10a+c)+ (100a+10c+a)+ (100c+10a+a)
=> 222a+111c=1332……111(2a+c)=1332……2a+c=12

(1) c=3
2a+3=12……2a=9
Not possible
Sufficient

(2) a=2
a) When a=b…..2*2+c=12c=8, so Sum could be 822+228+282…..Possible a=b
b) When a is not equal to b…..a,b,c can be 2,1,3….
Insufficient


A

How is this question different from
https://gmatclub.com/forum/positive-int ... l#p3085030

Please help
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