If 0

Question

If 0 < x < y, what is the value of \frac{(x + y)^2}{(x- y)^2} ? (1) x^2 + y^2 = 3xy (2) xy = 3 15.gif

dosteria · Answer

1)
x^2+y^2=3xy => x^2+y^2-2xy=xy => (x-y)^2=xy

So you can replace : (x+y)^2/xy

And then just finish the work : (x+y)^2/xy => (x^2+y^2+2xy)/xy => (3xy+2xy)/xy => 5

1 is enough

2) not enough. (x+y)^2/(x-y)^2 => (x^2+y^2+2xy)/(x^2+y^2-2xy) => (x^2+y^2+6)/(x^2+y^2-6) => you can't know the value of x^2 or y^2

Hope it helps.

Bunuel · Answer

If 0 < x < y, what is the value of (x + y)^2/( x- y)^2?

\frac{(x + y)^2}{( x- y)^2}=\frac{x^2+2xy+y^2}{x^2-2xy+y^2}

(1) x^2 + y^2 = 3xy. Substitute: what is the value of  \frac{x^2+2xy+y^2}{x^2-2xy+y^2}=\frac{3xy+2xy}{3xy-2xy}=\frac{5xy}{xy}=5 . Sufficient.

(2) xy = 3. Not sufficient.

Answer: A.

Dondarrion · Answer

Can someone explain how to tackle (2)?

I started testing numbers with x=1 and y=3, result is 16. Then I went to x= \frac{1}{2}  and y=6, but I quickly got bogged down in math and I was unable to prove that it is insufficient.

What is the shortcut I am missing to see that xy=3 is insufficient?

Thanks!

ENGRTOMBA2018 · Answer

You can clearly see that you ar egiven that x<y and that both x,y are >0. Statement 2 tells you that 2 positive number s(integers or not) give you a product of 3. Clearly, you can have different combinations that give you xy=3 but will definitely give you different values of x+y and let alone for (x+)^2/(x-y)^2. This makes this statement not sufficient.

With x=1 and y=3, the value should be 4 and not 16 (besides the point). As for x=.5 and y =6, you get (x+y)^2 = 6.5^2 and (x-y)^2 = 5.5^2 ---> 6.5^2/5.5^2 = (13/11)^2 = a value close to 1. Thus you get 2 different values for the expression under consideration, making this statement not sufficient.

Hope this helps.

mcelroytutoring · Answer

Attached is a visual that should help.

CrackverbalGMAT · Answer

If  0 < x < y , what is the value of  \frac{(x + y)^2}{(x- y)^2} ?

(1)  x^2+y^2=3xy

\frac{(x + y)^2}{(x- y)^2}  = \frac{ (x^2 + 2xy + y^2)}{(x^2 - 2xy + y^2)}

=  \frac{(3xy + 2xy)}{(3xy - 2xy)}  =  \frac{5xy}{xy}  =  5

Hence, Statement 1 alone is sufficient.

(2) xy=3

We will not be able to answer the question stem only with statement xy =3. Hence Statement 2 alone is insufficient.

Option A is the correct answer.

Hope this helps,
  Clifin J Francis,
GMAT SME

yziyue · Answer

Hi Bunuel,
What is the point of giving this information in the question stem: 0 < x < y?
I didn't need it in both statements and thought I did the question wrong even though my steps were correct. The only thing I could get from this info is that both x and y are positive numbers. But I don't see how x<y is a needed information. Am I missing any point here?

totaltestprepNick · Answer

A https://www.youtube.com/watch?v=3ScPLJB5m-o Nick Slavkovich, GMAT/GRE tutor with 20+ years of experience tutoring@totaltestprep.net

If 0 < x < y, what is the value of (x + y)^2/(x- y)^2?

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