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fameatop
A shorter method can be as below:
X+Y+Z = 6, where X, Y => 1 and Z > 1, so minimum value Z can have is 2
Distribute 1 to X and Y each and Z = 2
Then X+Y+Z = 2 now to find out how many cases can have X=1, distribute 2 to Y and Z, that is Y+Z=2 -> 3C1 -> 3 ways
All the cases, X+Y+Z = 2 -> 4C2 - 6
Hence 3/6 = 1/2 A)
If J/K = 1/2, K/L= 3/2, L/M=4, M/N= 5/3 & N/O= 1/5, what is the approximate integer value of \(\frac{JKL}{MNO}\)?
(A) 360
(B) 36
(C) 4
(D) 40
(E) 3
Answer
Explanation
(A) 360
(B) 36
(C) 4
(D) 40
(E) 3
Answer
Explanation
K = 2J
L=4J/3
M= J/3
N= J/5
O=J
\(\frac{JKL}{MNO}\) = 40
L=4J/3
M= J/3
N= J/5
O=J
\(\frac{JKL}{MNO}\) = 40
fameatop
The expression to be maximized is 2X+5 and should be an integer value, so 2X should be an integer. Hence X can be 60.5 , the value would be 126 D)
Tom wants to write GMAT, but because of unavailability of seats in his hometown he decides to schedule it in a nearby town that he is not fully aware of. On Test day he travels 10 mile due south followed by 20 miles west & finally 10 miles south again to reach the incorrect test center rather than travelling 10 mile due north followed by 20 miles east & finally 10 miles north again to reach the correct test center. What is the minimum distance Tom needs to travel so that he can appear for the test?
(A) 80
(B) 55
(C) 57
(D) 67
(E) 68
Answer
Explanation
(A) 80
(B) 55
(C) 57
(D) 67
(E) 68
Answer
Explanation
If we draw the traveled distance using straight lines, we will get Isosceles Right angle triangle with sides 40 & 40. We are asked to find the Hypotenuse of this triangle.
Hypotenuse will be 40\(\sqrt{2}\) = 56.56= 57 miles
Hypotenuse will be 40\(\sqrt{2}\) = 56.56= 57 miles
A cunning trader bought unknown quantities of two varieties of salt costing 5 & 8$ per ounce and mixes them with 18 ounces of sand, which is available free of cost, to produce adulterated salt, which the trader will sell at below market price. At what price should the trader sell the mixture so that he can make 12.5% profit?
(A) If sand is not mixed with the salt, then the cost price of the mixture is 50% more than the final cost price of adulterated mixture or 33% more than the final sales price of adulterated mixture.
(B) Two salts are mixed in a ratio of 2:1
Answer
Explanation
(A) If sand is not mixed with the salt, then the cost price of the mixture is 50% more than the final cost price of adulterated mixture or 33% more than the final sales price of adulterated mixture.
(B) Two salts are mixed in a ratio of 2:1
Answer
Explanation
In this question we have to find the cost price of adulterated mixture (2 types of salt & sand)
Let's assume that the cost price of adulterated mixture is 8c, so selling price will be 9c
Statement1:-If only two types of salts are mixed the cost price will be = 1.5 x cost price of adulterated mixture = 1.5 x 8c = 12c.
From this we can find that the 5 & 8$ salts are mixed in a ratio of (8-12c) & (12c-5).
Because the value of C is not known we can't find the value of this ratio.
Thus insufficient
Statement2:-Two salts are mixed in a ratio of 2:1.
From this we can find that if 5 & 8$ salts are mixed in a ratio of 2:1 , the cost price will be 6$/ounce
But we want the cost price of the mixture of salts & sand. We know that 18 ounces of sand is used.
In order to calculate the final cost price we should know either the amount of the salts, which is mixed with sand, or the ratio of salts & sand.
But we don't have the Exact amount of the salts or the the ratio of salts & sand.
Thus insufficient
Statement 1&2:-Combing both we will get the answer
Cost price of adulterated mixture will be 4$ or selling price will be 4.5$
Let's assume that the cost price of adulterated mixture is 8c, so selling price will be 9c
Statement1:-If only two types of salts are mixed the cost price will be = 1.5 x cost price of adulterated mixture = 1.5 x 8c = 12c.
From this we can find that the 5 & 8$ salts are mixed in a ratio of (8-12c) & (12c-5).
Because the value of C is not known we can't find the value of this ratio.
Thus insufficient
Statement2:-Two salts are mixed in a ratio of 2:1.
From this we can find that if 5 & 8$ salts are mixed in a ratio of 2:1 , the cost price will be 6$/ounce
But we want the cost price of the mixture of salts & sand. We know that 18 ounces of sand is used.
In order to calculate the final cost price we should know either the amount of the salts, which is mixed with sand, or the ratio of salts & sand.
But we don't have the Exact amount of the salts or the the ratio of salts & sand.
Thus insufficient
Statement 1&2:-Combing both we will get the answer
Cost price of adulterated mixture will be 4$ or selling price will be 4.5$
Simple concept but a very Challenging question
An inlet pipe fills tank A at a rate of 25 liter per minutes. 1st outlet pipe drawing water at a rate of 5 liter per minute from tank A is connected to bathroom & 2nd outlet pipe is connected to Tank B. The 2nd outlet pipe will draw water, at a rate of 15 liter per minute, only if the water level in Tank A is > 50%. One outlet pipe drawing water at a rate of 5 liter per minute from tank B is connected to Kitchen. Capacity of Tank A & B is 800 & 600 liter respectively. Both the tanks are empty at the beginning & all the taps are turned on since the beginning. How much less time (in minutes) will Tank B take to fill completely than the time taken by Tank A to fill completely from the moment Tank A starts transferring water to Tank B?
(A) 20
(B) 40
(C) 60
(D) 80
(E) 100
Answer
Explanation
An inlet pipe fills tank A at a rate of 25 liter per minutes. 1st outlet pipe drawing water at a rate of 5 liter per minute from tank A is connected to bathroom & 2nd outlet pipe is connected to Tank B. The 2nd outlet pipe will draw water, at a rate of 15 liter per minute, only if the water level in Tank A is > 50%. One outlet pipe drawing water at a rate of 5 liter per minute from tank B is connected to Kitchen. Capacity of Tank A & B is 800 & 600 liter respectively. Both the tanks are empty at the beginning & all the taps are turned on since the beginning. How much less time (in minutes) will Tank B take to fill completely than the time taken by Tank A to fill completely from the moment Tank A starts transferring water to Tank B?
(A) 20
(B) 40
(C) 60
(D) 80
(E) 100
Answer
Explanation
Net Filling rate for Tank A before it reaches 50% of capacity = (25-5) = 20 lit/min
Time taken by Tank A to fill initial 50% of capacity = 400/(25-5) = 20 min
Net Filling rate for Tank A after it reaches 50% of capacity = (25-5-15) = 5 lit/min
Time taken by Tank A to fill the remaining 50% of capacity = 400/(5) = 80 min
Net Filling rate for Tank B = (15-5) = 10 lit/min
Time taken by Tank B to fill completely = 600/10 = 60 min
Thus Tank B take will take (80-60) 20 min less to fill completely than the time taken by Tank A to fill completely from the moment Tank A starts transferring water to Tank B
Time taken by Tank A to fill initial 50% of capacity = 400/(25-5) = 20 min
Net Filling rate for Tank A after it reaches 50% of capacity = (25-5-15) = 5 lit/min
Time taken by Tank A to fill the remaining 50% of capacity = 400/(5) = 80 min
Net Filling rate for Tank B = (15-5) = 10 lit/min
Time taken by Tank B to fill completely = 600/10 = 60 min
Thus Tank B take will take (80-60) 20 min less to fill completely than the time taken by Tank A to fill completely from the moment Tank A starts transferring water to Tank B
Simple concept but very Tricky
An inlet pipe starts filling an empty tank A at a rate of 25 liter per minute at 11:00 am, while an outlet pipe draws water from tank A & fills empty tank B at a rate of 20 liter per minute only if the water level in Tank A is > 20%. Likewise, an outlet pipe draws water from tank B & fills empty tank C at a rate of 15 liter per minute only if the water level in Tank B is > 40%. Lastly, an outlet pipe draws water from tank C & fills empty tank D at a rate of 10 liter per minute only if the water level in Tank C is > 50%. Capacity of Tank A, B, C & D is 1000, 800, 600 & 400 liter respectively. At what time all the tanks will be completely filled?
(A) 12:24 noon
(B) 1:40 pm
(C) 1:48 pm
(D) 4:56 pm
(E) 5:40 pm
Answer
Explanation
An inlet pipe starts filling an empty tank A at a rate of 25 liter per minute at 11:00 am, while an outlet pipe draws water from tank A & fills empty tank B at a rate of 20 liter per minute only if the water level in Tank A is > 20%. Likewise, an outlet pipe draws water from tank B & fills empty tank C at a rate of 15 liter per minute only if the water level in Tank B is > 40%. Lastly, an outlet pipe draws water from tank C & fills empty tank D at a rate of 10 liter per minute only if the water level in Tank C is > 50%. Capacity of Tank A, B, C & D is 1000, 800, 600 & 400 liter respectively. At what time all the tanks will be completely filled?
(A) 12:24 noon
(B) 1:40 pm
(C) 1:48 pm
(D) 4:56 pm
(E) 5:40 pm
Answer
Explanation
Time taken by Tank A to fill initial 20% of capacity = 200/25 = 8 min
Net Filling rate for Tank A after it reaches 20% of capacity = (25-20) = 5 lit/min
Time taken by Tank A to fill the remaining 80% of capacity = 800/5 = 160 min
Tank A will take the longest to fill. By the time Tank A is full all the other tanks will be full.
Thus the time at which all the tanks will be full= 8+160 = 168 min = 2 hrs 48 minutes.
Net Filling rate for Tank A after it reaches 20% of capacity = (25-20) = 5 lit/min
Time taken by Tank A to fill the remaining 80% of capacity = 800/5 = 160 min
Tank A will take the longest to fill. By the time Tank A is full all the other tanks will be full.
Thus the time at which all the tanks will be full= 8+160 = 168 min = 2 hrs 48 minutes.
Attachments
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A water heater boils the water in 15 minutes on Low heat or in 10 minutes on Medium heat or in 5 minutes on High heat. On Sunday, water heater heats the water in 8 minutes. For how long heater was on Medium Heat mode?
(A) Capacity of Water heater is 25 liters.
(B) Ratio of efficiency on Low, Medium & High heat is 2:3:6
Answer
Explanation
(A) Capacity of Water heater is 25 liters.
(B) Ratio of efficiency on Low, Medium & High heat is 2:3:6
Answer
Soon
Explanation
Soon
A Train starts traveling from station A towards station B. The moment train starts traveling a Radar, situated at station B, emits a wave that travels towards the moving train at a rate of 50km/hr. The wave is reflected back to station B as soon as it hits the front of the train and this process goes on till train reaches station B. What is the total distance covered by the wave?
(A) Speed of the train is 25 Km/hr .
(B) Train takes 1 Hr to reach station B
Answer
Explanation
(A) Speed of the train is 25 Km/hr .
(B) Train takes 1 Hr to reach station B
Answer
Explanation
Soon
A guy standing at the platform sees a Train coming toward him . In order to touch the rear end of the train of the train, he starts running away from the train. At what speed should he run so that he could touch the rear end of the train?
(A) Speed of the train is 40 km/hr.
(B) The moment guy sees the front of the train, the distance between the guy & the train is 10 Km
Answer
Explanation
(A) Speed of the train is 40 km/hr.
(B) The moment guy sees the front of the train, the distance between the guy & the train is 10 Km
Answer
Explanation
Soon
prateekbhatt
Hi Prateek,
This is a Veritas question and thus a copyrighted material.
cyberjadugar
Joined: 28 Mar 2012
Last visit: 01 Apr 2026
Posts: 264
Location: India
GMAT 1: 640 Q50 V26
GMAT 2: 660 Q50 V28
GMAT 3: 730 Q50 V38
GMAT 3: 730 Q50 V38
Posts: 264
Parallelogram ABCD is to be constructed in the xy-plane such that the sides are parallel to x and y axis. The x and y coordinates of A, B, C and D are to be integers that lies between the lines |x-1| = 5 and |y+5| = 6. How many different parallelograms with these properties could be constructed?
(A) 10
(B) 110
(C) 1980
(D) 9900
(E) 4980
(A) 10
(B) 110
(C) 1980
(D) 9900
(E) 4980
Show SpoilerAnswer
(C)
For a given triangle with sides x,3x and 24, what is the value of the perimeter?
I. The perimeter is a perfect square.
II.(x-3)(x-10) = 0
_________________
I. The perimeter is a perfect square.
II.(x-3)(x-10) = 0
_________________
How many zeros exist in the end of the product of alphabets(a-z) where a = 4^4, b = 5^5, c = 6^6, ....z = 29^29?
a) 99
b) 100
c) 101
d)102
e)103
a) 99
b) 100
c) 101
d)102
e)103
swati007
I think, It is 100.
A zero is created when 2 is multiplied by 5. So we should find out how many multiplications of 2 and 5 are possible in the expression.
Obviously 2 will occur more frequently than does 5. So number of 5 in the above expression will determine the number of zeros.
5 can be found in following terms
5^5 = 5 times
10^10 = 10 times
15^15 = 15 times
20^20 = 20 times
25^25 = 50 times
Total = 100 times. So 100 zeros should be there.
thats right...
is the competition closed now? i didnt see any kudos to latest posts..
is the competition closed now? i didnt see any kudos to latest posts..
swati007
It's closed quite long back
Automated notice from GMAT Club BumpBot:
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This post was generated automatically.
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