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Updated on: 24 Sep 2025, 11:57
Originally posted by goodyear2013 on 13 Jan 2014, 13:07.
Last edited by Bunuel on 24 Sep 2025, 11:57, edited 1 time in total.
Last edited by Bunuel on 24 Sep 2025, 11:57, edited 1 time in total.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
62% (03:19) correct
38%
(03:11)
wrong
based on 537
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Not Attempted Yet
A woman is planning a trip that involves 3 connecting trains that depart from Stations X, Y, and Z, respectively. The first train leaves Station X every hour, beginning at 6 a.m., and arrives at Station Y 1(3/4) hours later. The second train leaves Station Y every half hour, beginning at 9 a.m., and arrives at Station Z 2(1/3) hours later. The third train leaves Station Z every 45 minutes, beginning at 8 a.m. What is the least total amount of time the woman must spend waiting between trains if all trains depart and arrive on schedule, and if she arrives at Station Z no later than 3:30 p.m.?
A. 15 minutes
B. 25 minutes
C. 1 hour 15 minutes
D. 1 hour 40 minutes
E. 4 hours 30 minutes
A. 15 minutes
B. 25 minutes
C. 1 hour 15 minutes
D. 1 hour 40 minutes
E. 4 hours 30 minutes
Show Spoiler OE
Trains coming from X arrive at Y at 45 minutes past the hour.
Trains leave Y on the hour and the half-hour. So minimum wait at Y will be 0:15.
This could be 8:45 − 9:00 am, 9:45 − 10:00 am, 10:45 − 11:00 am, etc.
Trains from Y will reach Z at 20 and 50 minutes past the hour, with the first arriving at 11:20.
Trains leave Z at various times, creating waits as short as 10 minutes (12:20-12:30) and as long as 40 minutes (11:50-12:30).
For shortest total waiting time possible, need to combine a 15-minute wait for the second train with a 10-minute wait for third train.
This will happen if the woman takes the 8:00 train from X, the 10:00 train from Y, and the 12:30 train from Z.
Hi, I found the situation of this question is not very clear.. I want to know how we can approach this, please.
Trains leave Y on the hour and the half-hour. So minimum wait at Y will be 0:15.
This could be 8:45 − 9:00 am, 9:45 − 10:00 am, 10:45 − 11:00 am, etc.
Trains from Y will reach Z at 20 and 50 minutes past the hour, with the first arriving at 11:20.
Trains leave Z at various times, creating waits as short as 10 minutes (12:20-12:30) and as long as 40 minutes (11:50-12:30).
For shortest total waiting time possible, need to combine a 15-minute wait for the second train with a 10-minute wait for third train.
This will happen if the woman takes the 8:00 train from X, the 10:00 train from Y, and the 12:30 train from Z.
Hi, I found the situation of this question is not very clear.. I want to know how we can approach this, please.
02 Mar 2015, 02:28
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goodyear2013
Make a departure arrival diagram to minimize the waiting time.
Attachment:
FullSizeRender.jpg [ 1.49 MiB | Viewed 13803 times ]
Trains depart from Y at 9/9:30/10/10:30 etc. This means a minimum wait of 15 mins is required at Y.
They arrive at Z at 11:20/11:50/12:20/12:50. They depart from Z at 8/8:45/9:30/10:15/11/11:45/12:30 and so on. Note that if she arrives at Z at 20 mins past the hour, she will need to wait for at least 10 mins for 12:30/3:30 etc train. If she arrives at 50 mins past the hour, again she needs to wait for at least 10 mins to take the 2 o clock train. So anyway 10 mins at Z is a given.
So minimum she will need to wait for 15+10 = 25 mins.
This works out if she takes 8 o clock train from X, reaches Y at 9:45, takes 10 o clock train from Y and reaches Z at 12:20 and takes 12:30 train from Z.
Answer (B)
19 Jun 2015, 07:16
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I would prefer back solving for this question.
Reached Z @ 3:30 PM, from Y-->Z it will take 140 minutes, so she should have started from Y @ 1:10 PM but trains from Y to Z leaves at every 30mins starting at 9am,therefore she should board into the train @1PM and wait at station Z for 10minutes for her next train from station Z.
Now, X --> Y journey:
To reach Y at 1PM she should start from X by 11AM atleast as, journey time is 105minutes .If she will start from station X by 11AM then she will reach Y by 12:45 PM, hence will wait for 15minutes before she board into 1PM train from station Y.
Total waiting time= 15+10=25 minutes.
Hope that was helpful.
Cheers,
Gaurav
Reached Z @ 3:30 PM, from Y-->Z it will take 140 minutes, so she should have started from Y @ 1:10 PM but trains from Y to Z leaves at every 30mins starting at 9am,therefore she should board into the train @1PM and wait at station Z for 10minutes for her next train from station Z.
Now, X --> Y journey:
To reach Y at 1PM she should start from X by 11AM atleast as, journey time is 105minutes .If she will start from station X by 11AM then she will reach Y by 12:45 PM, hence will wait for 15minutes before she board into 1PM train from station Y.
Total waiting time= 15+10=25 minutes.
Hope that was helpful.
Cheers,
Gaurav
