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17 Oct 2018, 02:51
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
80% (01:23) correct
20%
(01:19)
wrong
based on 220
sessions
History
Date
Time
Result
Not Attempted Yet
2x + y years ago, Roberto was 3x + y years old. How many years old was Roberto x years ago?
A. x
B. 4x + 2y
C. 5x + 2y
D. 6x + 2y
E. 6x + y
A. x
B. 4x + 2y
C. 5x + 2y
D. 6x + 2y
E. 6x + y
17 Oct 2018, 03:19
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Bunuel
2x + y years ago, Roberto was 3x + y years old, so today he will be (3x+y) + 2x+y = 5x + 2y years old.
So, x years ago from today, Roberto was (5x+2y) - x = 4x + 2y years old.
Hence Option (B) is our choice.
Best,
GLadi
General Discussion
17 Oct 2018, 03:58
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The solution can be best demonstrated in a table.
If he was 3x+y years old, 2x+y years ago.
The now he will be \(3x + y + 2x + y = 5x + 2y\)
X years ago is basically 5x + 2y - x = 4x + 2y
Answer choice B
If he was 3x+y years old, 2x+y years ago.
The now he will be \(3x + y + 2x + y = 5x + 2y\)
X years ago is basically 5x + 2y - x = 4x + 2y
Answer choice B
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17 Oct 2018, 06:11
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Now, Roberto is (3x+y) + (2x + y) = 5x + 2y years old
x years ago, he was 5x+2y - x = 4x + 2y years old.
Hence Option B.
Now, another way is to plug in numbers, say x = 1, y = 1.
So, 2*1 + 1 = 3 years ago Roberto was 3*1 + 1 = 4 years old. So, now, Roberto is 4+3 = 7 years old, x = 1 year ago, he was 6 years old. Check options now.
A: 1, Incorrect
B: 6, Correct
C: 7, Incorrect
D: 8, Incorrect
E: 7, Incorrect
Hence Option B again!
x years ago, he was 5x+2y - x = 4x + 2y years old.
Hence Option B.
Now, another way is to plug in numbers, say x = 1, y = 1.
So, 2*1 + 1 = 3 years ago Roberto was 3*1 + 1 = 4 years old. So, now, Roberto is 4+3 = 7 years old, x = 1 year ago, he was 6 years old. Check options now.
A: 1, Incorrect
B: 6, Correct
C: 7, Incorrect
D: 8, Incorrect
E: 7, Incorrect
Hence Option B again!
