If, in the figure above, square S2 has side of length 2 and square S1

Question

https://gmatclub.com/forum/download/file.php?id=61807 If, in the figure above, square S2 has side of length 2 and square S1 has side of length 1, what is the equation of line m? A. y = x/3 + 1 B. y = x/2 + 1 C. y = x/3 D. y = x/2 E. y = x - 1 Project PS Butler Subscribe to get Daily Email - Click Here | Subscribe via RSS - RSS download.png

sumitkrocks · Answer

Line m passes through (0,1) and (3,2) and equation of the line passing through these coordinates is

\frac{(y-1) }{x }=\frac{1}{3}

y=  \frac{x}{3}  + 1

Option A is correct

asishron29181 · Answer

Line passes through points (0,1) and (3,2)
Slope of m = y2 - y1 / x2 - x1
=1/3

Equation of line,
y -y1 = m (x-x1)
y -1 = 1/3 x
y= x/3 +1

IMO A

TarunKumar1234 · Answer

Equation of st. line passes through (0,1) and (3,2) y-1 = (2-1)/3 * (x-0) or, y= x/3 +1 So, I think A.

IanStewart · Answer

There are great solutions above. You can also notice that the line meets the y-axis at y = 1, so the y-intercept is 1, and the equation must look like "y = mx + 1", where m is the slope. So the answer must be A or B, and if you can see that the slope is less than 1/2 (if the slope were 1/2, the line would meet the second square at the midpoint of its top side), that alone lets you correctly pick A, or you can plug the other point on the line, (3, 2), into either A or B to see which of the two answers must be right.

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Showmeyaa · Answer

Line passes through points (0,1) and (3,2)
 Slope = \frac{2-1}{3-0} = \frac{1}{3} 
So,  y = \frac{1}{3}x + b 
Now, take any of the above points and plug in to find the find the value of b(y intercept):
Let's pick x = 3, y =2
So,  2 = \frac{1}{3} * 3 + b 
b = 1.
Our equation becomes,  y = \frac{1}{3}x + 1  - (A), IMO!

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If, in the figure above, square S2 has side of length 2 and square S1

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GMAT Problem Solving (PS) Questions

If, in the figure above, square S2 has side of length 2 and square S1

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