I'd just draw pictures here to see what can happen. Our two lines meet at a point in the first quadrant (where x and y coordinates are positive), at a point (a, b), where a > b, so where the x-coordinate exceeds the y-coordinate. That means our intersection point lies below the line y=x, but above the x-axis. Line m has a slope between 0 and 1, so as it moves right, it's rising, but slowly. The perpendicular line n, therefore, is falling and quickly as it moves to the right.
So, if line n has a point on it (a, b) above the x-axis in the first quadrant, and then is falling quickly as you move right from that point, it must hit the x-axis further to the right of that point, so its x-intercept must be positive, and I must be true.
If line m has a positive slope, independent of any other information provided, the product of its x and y intercepts will be negative (or zero if it passes through the origin). You can see that just considering two cases: if its x-intercept is negative, then it rises moving right from there, so has a positive y-intercept. If its x-intercept is positive, it falls moving left from there, so its y-intercept is negative. So II must be true.
III need not be true, because the x-intercept of line m could be negative one trillion if it has a very shallow slope.
I think there's a typo in the answer choices - I imagine answer D is meant to read "I and II only", and not "I and III only". (edit - that has since been fixed in the OP)
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