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pamma
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pamma
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answer is correct but can u explain this problem
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pamma
answer is correct but can u explain this problem
number of nepalese can sit in (3-1)!...let the indians sit in 4! ways..Total ways = 4! * 3! = 144
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Heyy has anyone here given NMAT and what’s considered to be a good score for it
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SATYAM7777
number of nepalese can sit in (3-1)!...let the indians sit in 4! ways..Total ways = 4! * 3! = 144
Why don’t we do 3! Even for Indian like we did for Nepalese?
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Inspirestella
Why don’t we do 3! Even for Indian like we did for Nepalese?
Because after seating nepalese, 4 seats were left for 4 indians.
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pamma
my answer is also 29/96
How can the denominator be 96 when the total employees are divided 3:2 between full and part time?

HarkiratTalwar
How can the denominator be 96 when the total employees are divided 3:2 between full and part time?
My bad - read 3/5 as fraction and not ratio
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pamma
my answer is also 29/96
Is this the correct answer?
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Inspirestella
Is this the correct answer?
Yes this and 3/10 both are correct answers
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aditya.khare
Yes this and 3/10 both are correct answers
How can there be 2 correct answer?
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Inspirestella
How can there be 2 correct answer?
Both comes out to be 0.3. Just a slight change in the way of calculation.

Also, I think it’s easier to say that for every 10 employees 3 are eligible for bonus, actually 3/10 should be the proper answer.
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Can you explain how did you get 3/10. I did get 29/96
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Inspirestella
Can you explain how did you get 3/10. I did get 29/96
Yes. The ratio is 3:5. So instead of solving directly using this ratio, I assumed there are 300 permanent employee and 500 non permanent, 800 total employee. Now if you calculate you’ll get 3/10.
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300 - 1/4 = 75
500 - 1/3 = 166.67 (not possible since people)

aditya.khare
Yes. The ratio is 3:5. So instead of solving directly using this ratio, I assumed there are 300 permanent employee and 500 non permanent, 800 total employee. Now if you calculate you’ll get 3/10.
In such cases, always try to take the product of denominators (or LCM in some cases where possible) for easier calculations
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HarkiratTalwar
300 - 1/4 = 75 500 - 1/3 = 166.67 (not possible since people)
Approximation? 165.
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A school administrator will assign each student in a group of N students to one of M classrooms. If 3<M<13<N, is it possible to assign each of the N students to one of the M classrooms so that each classroom has the same number of students assigned to it?

(1) It is possible to assign each of 3N students to one of M classrooms so that each classroom has the same number of students assigned to it.

(2) It is possible to assign each of 13N students to one of M classrooms so that each classroom has the same number of students assigned to it.

Can someone give an explained solution for this question ?
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muskanrajyan5
A school administrator will assign each student in a group of N students to one of M classrooms. If 3<M<13<N, is it possible to assign each of the N students to one of the M classrooms so that each classroom has the same number of students assigned to it? (1) It is possible to assign each of 3N students to one of M classrooms so that each classroom has the same number of students assigned to it. (2) It is possible to assign each of 13N students to one of M classrooms so that each classroom has the same number of students assigned to it.
What is the answer? I think it’ll be E.
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muskanrajyan5
A school administrator will assign each student in a group of N students to one of M classrooms. If 3<M<13<N, is it possible to assign each of the N students to one of the M classrooms so that each classroom has the same number of students assigned to it? (1) It is possible to assign each of 3N students to one of M classrooms so that each classroom has the same number of students assigned to it. (2) It is possible to assign each of 13N students to one of M classrooms so that each classroom has the same number of students assigned to it.
“is it possible to assign each of the N students to one of the M classrooms so that each classroom has the same number of students” simply means is N divisible by M? That is, N/M?

1) given 3N is divisible by M

Now, since M is between 3 and 13 and N is more than 13, this is not sufficient.

Let’s say, M = 6, N = 60. 3N/M

3(60)/6 = Integer value.

So, 60/6 = N/M = integer = yes possible to arrange each student to each class.

However, if, M = 12 and N = 16.

3(16)/12 = 4 = integer value.

But, N/M = 16/12 is not an integer.

So, we may arrange or we may not arrange equally. Insufficient.

B) given, 13N/M. We know 3<M<13<N. M has to be less than 13. That is M cannot be a multiple of 13 to cancel out that 13 in the numerator. Thus, N has to cancel out M in denominator to give us 13N/M as an integer. That is N/M is an integer.

Thus, sufficient. Answer is B.

The concept is basically testing number properties. Also, since we are dealing with students, we can to keep in my the question is testing on integer values, since we cannot get 1.5 student or something.

Hope this helps. :)

*we need to keep in mind that question is testing on integer
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