y=(x^2-x)(x-2)=x(x-1)(x-2). So, y will be 0 when x=0,1, and 2, that is the curve will cut graph at 0, 1 and 2. Only C and D left........... Next, when x>2, all three x, x-1 and x-2 will be positive, and product of three positive is positive. Thus after cutting x-axis at 2, the line should give y as positive always..... OR You could just take x as 3, and see that y=3*1*2=6. D gives you positive value while C gives a negative value for y at x=3...answer is D