Practice Questions Chat

This question can be done with pure logic too, so circles, i.e., geometry can be avoided all together. It is given that x^2 + y^2 = 100, and we know that square of any number is always greater zero (or equal to zero if the number itself is zero). This means, if two squares are added, either of them cannot be more than the sum. Thus, x^2 and y^2 individually cannot be more than 100...and if either of them is equal to 100, the other is equal to zero. Thus, we can conclude that x^2 and y^2 are both less than (or equal) to 100. If x^2 is less than 100, it means x is between -10 and +10 (negative square is also positive). Same with y......Now if I take their absolute values, i.e., |x| and |y|, I can eliminate negative numbers and conclude that |x| and |y|, both individually lie between 0 to 10 (including 0 and 10). Thus one cannot be greater than the other by more than 10....if one is 0, the maximum other can be is 10 but NOT more.....which is basically option C. This way, you eliminate the geometry part of things and solve by logic. I don’t think GFE Quant has any question that can be solved ONLY with geometry.