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WA@jpg805
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What’ll be the 8th one?🤔
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3*3*2*2*5*5*5

?
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Its 1
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1?

Yeah
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dhrititrehan
3*3*2*2*5*5*5
This has 3 fives so can’t be a perfect square
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Ok got it. So technically, if we look at 2^2 *3^2 * 5^3,
Simplify it to reflect perfect square->
(2^2 * 3^2 * 5^2) * 5
If we are to find various combinations of the term in the brackets which includes 3 perfect squares
N! = 3! =6
Adding 2 more factors “1” and the term itself (2^2 * 3^2 * 5^2)
6+2=8
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Integers having odd numbers of factors MUST be perfect squares. So 4500 = 2^2*3^2*5^3 . In this case, only perfect squares we will consider for evaluating odd factor (2,3,5), Now the question has asked for numbers of factors Therefore, by using the property a^p*b^q*c^r = (p+1)(q+1)(r+1) >>>>>> (1+1)(1+1)(1+1) = 8

Pleas throw your views on this soln.
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Check out a new question from GMAT Club Tests:

a-fruit-vendor-has-a-total-of-80-apples-oranges-and-bananas-in-444596.html

Saks116
How many factors of 4500 have odd number of factors?

A) 4
B) 6
C) 8
D) 12
E) 16
This question is discussed here: how-many-factors-of-4500-have-odd-number-of-factors-314697.html

Hope it helps.
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Can you explain the last equation and what property is that- I have understood the answer but this looks really efficient
To find the number of factors you add 1 to each power and multiply them
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