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This has 3 fives so can’t be a perfect square

Ok got it. So technically, if we look at 2^2 *3^2 * 5^3, Simplify it to reflect perfect square-> (2^2 * 3^2 * 5^2) * 5 If we are to find various combinations of the term in the brackets which includes 3 perfect squares N! = 3! =6 Adding 2 more factors “1” and the term itself (2^2 * 3^2 * 5^2) 6+2=8

can someone explain this question to me a-train-s-journey-is-disrupted-due-to-an-accident-on-its-track-327556.html

Integers having odd numbers of factors MUST be perfect squares. So 4500 = 2^2*3^2*5^3 . In this case, only perfect squares we will consider for evaluating odd factor (2,3,5), Now the question has asked for numbers of factors Therefore, by using the property a^p*b^q*c^r = (p+1)(q+1)(r+1) >>>>>> (1+1)(1+1)(1+1) = 8 Pleas throw your views on this soln.

Check out a new question from GMAT Club Tests: a-fruit-vendor-has-a-total-of-80-apples-oranges-and-bananas-in-444596.html This question is discussed here: how-many-factors-of-4500-have-odd-number-of-factors-314697.html Hope it helps.

Check out a new question from GMAT Club Tests: three-business-partners-alex-ben-and-carlos-shared-all-the-revenue-444601.html

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