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04 Nov 2015, 19:11
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D
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Difficulty:
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64% (02:03) correct
36%
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wrong
based on 421
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A set of 11 positive integers has an average of 25. Which of the following is the greatest possible value for the median of this set?
A) 25
B) 30
C) 36
D) 45
E) 46
QUANT 4-PACK SERIES Problem Solving Pack 3 Question 3 A set of 11 positive integers...
48 Hour Window Answer & Explanation Window
Earn KUDOS! Post your answer and explanation.
OA, and explanation will be posted after the 48 hour window closes.
This question is part of the Quant 4-Pack series
Scroll Down For Official Explanation
A) 25
B) 30
C) 36
D) 45
E) 46
QUANT 4-PACK SERIES Problem Solving Pack 3 Question 3 A set of 11 positive integers...
48 Hour Window Answer & Explanation Window
Earn KUDOS! Post your answer and explanation.
OA, and explanation will be posted after the 48 hour window closes.
This question is part of the Quant 4-Pack series
Scroll Down For Official Explanation
04 Nov 2015, 20:54
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EMPOWERgmatRichC
hello,
for the median to be max , we should take all the values below meadian to be the lowest and the remaining values to be the same..
here 1 is the lowest value(positive int) so the lowest 5 int will equal 5..
remaining 6= 25*11-5=270..
therefore each valueof these 6 int =270/6=45
ans D
General Discussion
05 Nov 2015, 01:07
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Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.
A set of 11 positive integers has an average of 25. Which of the following is the greatest possible value for the median of this set?
A) 25
B) 30
C) 36
D) 45
E) 46
In order to make the median maximum the 6th large number(=median number) should be as great as possible. That means the greater numbers than 6th number should be as small as possible. So all the numbers which are greater than 6th number should be equal to 6th number.
Moreover the numbers which are less than 6th number should be as small as possible and they should be all equal with similar reason. That is first 5 numbers should be 1.
So the sum of remaining 6 numbers is 11*25-5 = 270. That is remaining numbers should be (270/6=)45.
So the answer is (D).
A set of 11 positive integers has an average of 25. Which of the following is the greatest possible value for the median of this set?
A) 25
B) 30
C) 36
D) 45
E) 46
In order to make the median maximum the 6th large number(=median number) should be as great as possible. That means the greater numbers than 6th number should be as small as possible. So all the numbers which are greater than 6th number should be equal to 6th number.
Moreover the numbers which are less than 6th number should be as small as possible and they should be all equal with similar reason. That is first 5 numbers should be 1.
So the sum of remaining 6 numbers is 11*25-5 = 270. That is remaining numbers should be (270/6=)45.
So the answer is (D).
