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Bunuel
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Bunuel
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Bunuel, that is an amazing shortcut. For those who didn't see the shortcut (like me), this is also the sum of a geometric series, with the first term a = 20, and the common ratio r= 1/3. 20*(1/(1-1/3)) = 30.
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I think this is a high-quality question and I agree with explanation. OMG!! I spent 5+ minutes trying to figure out the Damn GP and still got it wrong!! And I feel the most stupid person alive after seeing the solution!! Haha!
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Raunak_Bhatia
Damn!!! I feel so stupid seeing this solution, (I literally was calculating to and fro distance covered by the fly) Sometimes it just doesn't strike you in the test environment.

Same here... lol :roll:
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D4kshGargas
Raunak_Bhatia
Damn!!! I feel so stupid seeing this solution, (I literally was calculating to and fro distance covered by the fly) Sometimes it just doesn't strike you in the test environment.

Same here... lol :roll:


same here. too

but i tried to solve it as below in stupid way:)
It would need formula of infinite ratio : sum of total fractions dividing by r each time = r/1-r

Fly speed = 10km/h
each hikers speed = 5km/h

So whatever time they cover, relative distance would be ==> fly: hiker = 2:1
each time distance would be reduced


1st meet distance ==> fly: meet = 20:10 ( total distance to cover 30 km)
2nd meet distance==> fly: meet = 6.66:3.34 ( total distance to cover 10 kms)
3rd distance meet ==> fly: meet = 2.22:1.11 ( total distance to cover 3.33 kms)
from 4th onwards: distance would be less than 1 km each time
Hence equation,
20+ 20/3 +20/9+ 20/27 + .... = 20 ( 1/{1-1/3}) = 20 *3/2= 30 kms ( infinite formula= r/1-r; here r = 1/3
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I think this is a high-quality question and I agree with explanation. The question is very very simple if you understand it and is only made "complicated" through the story of the fly. Its pretty straightforward otherwise. I liked how they tried to trick us using the wordy question. :)
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I think this is a high-quality question and I can see it in the official GMAT exam.

an even shorter cut is to realize that the two hikers cover 10km together in one hour, which matches with what the fly covers in one hour.
realizing that alone let us quickly solve this question without the need for calculations.
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Bunuel
Two hikers simultaneously start walking towards each other from Kensington, MD and Reston, VA, which are 30 km apart. Both hikers walk at a constant speed of 5 km/hour each. At the same time, a fly takes off from Kensington and flies towards the Reston hiker at a speed of 10 km/hour. When the fly reaches the Reston hiker, it immediately turns around and flies back to the Kensington hiker, and it continues to do so until the hikers meet. At the moment when the hikers meet, the fly lands on the shoulder of the Kensington hiker. How many kilometers has the fly flown in total?

A. 25
B. 30
C. 37.5
D. 45
E. 60

Please help me understand where I went wrong.
Two people moving at same speed towards each other would meet at the center. So they meet at point which is 15km away from both ends (where fly lands on shoulder).

Fly is flying at 10km/h and Robert hiking at 5km/h. So they would meet at distance covered by fly (say fd = 10t), Robert rd = 5t
here t is same.
fd/10=rd/5 -- i

fd+rd = 30
rd= 30-fd

in i
fd/10= (30-fd)/5
fd/2=30-fd
fd=60-2fd
3fd= 60
fd=20

so fly covered 20km before it met robert, from here it starts to fly back to the point where robert and Kensington met (which we calculated was center)

By this logic now fly has to cover 5km.
Total distance = 25km.

one fault in my logic is, when the fly flies back from here, it would reach the center before Robert. But I couldn't really understand how to accomodate that, so I just let the fly to the midpoint because thats where the hikers meet. Please help me with this.
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Bunuel
Two hikers simultaneously start walking towards each other from Kensington, MD and Reston, VA, which are 30 km apart. Both hikers walk at a constant speed of 5 km/hour each. At the same time, a fly takes off from Kensington and flies towards the Reston hiker at a speed of 10 km/hour. When the fly reaches the Reston hiker, it immediately turns around and flies back to the Kensington hiker, and it continues to do so until the hikers meet. At the moment when the hikers meet, the fly lands on the shoulder of the Kensington hiker. How many kilometers has the fly flown in total?

A. 25
B. 30
C. 37.5
D. 45
E. 60

Please help me understand where I went wrong.
Two people moving at same speed towards each other would meet at the center. So they meet at point which is 15km away from both ends (where fly lands on shoulder).

Fly is flying at 10km/h and Robert hiking at 5km/h. So they would meet at distance covered by fly (say fd = 10t), Robert rd = 5t
here t is same.
fd/10=rd/5 -- i

fd+rd = 30
rd= 30-fd

in i
fd/10= (30-fd)/5
fd/2=30-fd
fd=60-2fd
3fd= 60
fd=20

so fly covered 20km before it met robert, from here it starts to fly back to the point where robert and Kensington met (which we calculated was center)

By this logic now fly has to cover 5km.
Total distance = 25km.

one fault in my logic is, when the fly flies back from here, it would reach the center before Robert. But I couldn't really understand how to accomodate that, so I just let the fly to the midpoint because thats where the hikers meet. Please help me with this.

The combined speed of the fly and the hiker from Reston is 10 + 5 = 15 km/h. Thus, they will meet after 30/15 = 2 hours.

In 2 hours, the fly would cover 2*10 = 20 km, and each hiker would cover 2*5 = 10 km:

K ----------(10 km)---------- (Fly meets Hiker 1) ----------(10 km)---------- (Hiker 2) ----------(10 km)---------- R

Therefore, the distance between the fly and the hiker from Reston would be 10 km, which they would cover in 10/15 = 2/3 of an hour.

In 2/3 of an hour, the fly would cover an additional 2/3*10 = 20/3 km, and each hiker would cover 2/3*5 = 10/3 km:

K -----------(40/3 km)--------------- (Hiker 1) ----(10/3 km)---- (Fly meets Hiker 2) -----------(40/3 km)--------------- R

...

Continuing this pattern, each time the fly covers a third of the distance it did previously, we must sum up the infinite sequence: 20 + 20/3 + 20/9 + ... For an infinite geometric sequence with a common ratio |r| < 1, the sum can be calculated as sum = b/(1 - r), where b is the first term. Therefore, the sum is 20/(1 - 1/3) = 30.

That being said, solving this question using the method shown in the official solution is much quicker. Thus, I suggest understanding that one.
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You are unbelievable Bunuel!! I should be punished for making it so cumbersome, calculating the fly to and fro
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When you did all the complicated engineering of the flying back and forward ... then all the sudden see through the reasoning ... It’s like a math joke XD! I love it ! And its such a great question!
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Bunuel
Official Solution:

Two hikers simultaneously start walking towards each other from Kensington, MD and Reston, VA, which are 30 km apart. Both hikers walk at a constant speed of 5 km/hour each. At the same time, a fly takes off from Kensington and flies towards the Reston hiker at a speed of 10 km/hour. When the fly reaches the Reston hiker, it immediately turns around and flies back to the Kensington hiker, and it continues to do so until the hikers meet. At the moment when the hikers meet, the fly lands on the shoulder of the Kensington hiker. How many kilometers has the fly flown in total?

A. 25
B. 30
C. 37.5
D. 45
E. 60


To calculate how long the fly was flying, we first determine the time it takes for the hikers to meet. Since the hikers are walking towards each other at a speed of 5 km/hour each, their combined speed is 10 km/hour. Therefore, they will meet after \(\frac{30}{10}=3\) hours.

This means that the fly was flying for 3 hours at a speed of 10 km/hour, covering a distance of 30 km.


Answer: B
Bunuel I have a doubt here. I agree that the hikers meet in 3 hours where both have covered 15km from K and R respectively. That means they meet at the midpoint of the path between K and R. Now we're saying that the fly has flown for 3 hours so it covered a total distance of 30km. However, the question states that the fly started from K at the same time as the hikers did. This means the hiker from K and the fly both started at the same time. If from that point, the fly covers 30km in 3 hours, how will the fly be at the mid point of the path between K and R? That means the fly can't land on the shoulder of the Kensington hiker. Because at 30km the
fly will be exactly at point R. The question statements seem to contradict each other. Can you please explain how this if possible? Or where I'm wrong in my analysis here?
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siddhantvarma
Bunuel
Official Solution:

Two hikers simultaneously start walking towards each other from Kensington, MD and Reston, VA, which are 30 km apart. Both hikers walk at a constant speed of 5 km/hour each. At the same time, a fly takes off from Kensington and flies towards the Reston hiker at a speed of 10 km/hour. When the fly reaches the Reston hiker, it immediately turns around and flies back to the Kensington hiker, and it continues to do so until the hikers meet. At the moment when the hikers meet, the fly lands on the shoulder of the Kensington hiker. How many kilometers has the fly flown in total?

A. 25
B. 30
C. 37.5
D. 45
E. 60


To calculate how long the fly was flying, we first determine the time it takes for the hikers to meet. Since the hikers are walking towards each other at a speed of 5 km/hour each, their combined speed is 10 km/hour. Therefore, they will meet after \(\frac{30}{10}=3\) hours.

This means that the fly was flying for 3 hours at a speed of 10 km/hour, covering a distance of 30 km.


Answer: B
Bunuel I have a doubt here. I agree that the hikers meet in 3 hours where both have covered 15km from K and R respectively. That means they meet at the midpoint of the path between K and R. Now we're saying that the fly has flown for 3 hours so it covered a total distance of 30km. However, the question states that the fly started from K at the same time as the hikers did. This means the hiker from K and the fly both started at the same time. If from that point, the fly covers 30km in 3 hours, how will the fly be at the mid point of the path between K and R? That means the fly can't land on the shoulder of the Kensington hiker. Because at 30km the
fly will be exactly at point R. The question statements seem to contradict each other. Can you please explain how this if possible? Or where I'm wrong in my analysis here?


The fly flies back and forth between the two hikers, not in just one direction. The key point is simple: the total distance covered by the fly is time * speed. Since the fly was flying for 3 hours, it covered 3 * 10 = 30 kilometers.
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I like the solution - it’s helpful. How about this one?

As they both are at the same constant speed, they will meet at the halfway point, which is 15 KM. To get there, you need 3 hours (15KM/5kmh).

Hearsay, so flying would constantly fly between two hikers for 3 hours, which means it would cover 3 hours * 10Kmh = 30 KM Distance.
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I don’t quite agree with the solution. the speed of the fly will be 15 kmph (10 km + 5km) as she is flying towards a person who is also walking towards the fly. therefore, we should consider relative speed in this case
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Udhayveerr
I don’t quite agree with the solution. the speed of the fly will be 15 kmph (10 km + 5km) as she is flying towards a person who is also walking towards the fly. therefore, we should consider relative speed in this case

You're mixing up the concept. Relative speed applies when calculating how long two objects take to meet.

But in this case, the fly is not trying to "meet" anyone in the sense of a single event, it's just continuously flying at 10 km/h for however long the hikers are walking. That time is 3 hours, based on the hikers’ relative speed.

So the fly flies at a constant 10 km/h for 3 hours, covering 30 km in total. No need to use relative speed for the fly's motion here. The solution is correct.

Check and review the full discussion above carefully for more clarity.
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I like the solution - it’s helpful.
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