Given: When a certain number X is divided by 63, the remainder is 27.
Asked: What is the remainder when X is divided by 7?
When a certain number X is divided by 63, the remainder is 27.
X = 63k + 27 ; where k is an integer
X = 7*9k + 7*3 + 6 = 7(9k+3) + 6 = 7m + 6; m = 9k + 3 and is an integer.
The remainder when X is divided by 7 is 6.
arixlove
"When a certain number X is divided by 63, the remainder is 27. What is the remainder when X is divided by 7?"
I'm stuck with a point in the solution of this problem, because after arriving to this equation : X=9Q+27/7, then 27/7=3+ 6/7 so remainder is 6....
I don't understand why the remainder is not 27 already, as the formula is X=Q+remainder/divisor, and the way X is expressed already gives r... Can you explain it in detail please?