Official ExplanationGraph the equations \(y = 3x – 2\) and \(y = x^2 + 3\) in the xy-plane, noting that the first is a line with slope 3 and y-intercept (0, –2), and that the second is an upward pointed parabola with yintercept (0, 3). The parabola is always above the line, having a greater y value, so \(x^2 + 3 > 3x – 2\) for all values of x.
(A).
*Plug in numbers for x. For x < 0,
(A) is positive, while
(B) is negative, so
(A) is greater. If \(x = 0,\) then
(A) \(= 3 >\)
(B) \(= –2.\) If \(x = 1,\) then
(A) \(= 4 > \)
(B) \(= 1.\) For large values of \(x, x^2 > 3x,\) so
(A) is greater.
Answer: AAttachment:
GMAT-Club-Forum-7qt17pdl.png [ 74.06 KiB | Viewed 92 times ]