Raj played three rounds of a game of chance. In each round he doubled the amount with himself and then gave a certain amount to his friend. The amount he gave his friend in each round was a quarter of his gain in the first round. If he had instead given to his friend in each round an amount equal to half of his gain in the first round he would have finally remained with rs 70 less than he actually did. Find the amount he started with in rs?

A. 80
B. 160
C. 40
D. 60

sometimes the wording of the questions confuse me


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this will be relatively easy if we chose 4x as the amount he starts with as we know that we want to give the quarter of the amount he won in the first round to his friend.

so
at start he has 4x

we doubled that in first round so now has 8x ( so he won 4x ) and quarter of that is x , this x is waht he gives to his friend ...so he is left with ( 4x + 4x -x) = 7x

after second round 14 x after third round 28 x ....and he gives x+x+x = 3x to his frnd so left with 25 x

second case when he gives double of what he won to his frnd

at start 4x

he doubles it to 8x ...so half of what he won he gives to his frnd i.e 2x so end of first round he is left with ........8x - 2x =6x

after second round he doubles to 12 x and then aftewr third 24 x ..but he gives 2x+2x+2x to his frnd so he is left with 24-6 = 18 x


now 25x-18 x = 70

x = 10

so initial amount = 40

OMG, i spend too much time on this question. I did not read the question carefully, the amount given to the friend is not equal 1/4 or 1/2 the gain in the previous round.

It seems there is no other way, but to test each option choice.