Bunuel wrote:

Randall purchased a shirt for $19.44 using a $20 bill. If his correct change was returned in only dimes ($0.10) and pennies ($0.01), how many coins could Randall have received?

(A) 9

(B) 21

(C) 29

(D) 37

(E) 44

Randall received a change of $0.56.

Let \(d\) be the # of dimes & \(p\) be the # of pennies Randall got in return.

Hence we have, \(0.10d + 0.01p = 0.56\)

Multiplying by 100 on both sides, we get

\(10d + p = 56\), hence (d,p), that satisfy the equation are (1,46), (2,36), (3,26), (4,16), (5,6)

# of coins received by Randall can be 47 or 38 or 29 or 20 or 11.

Answer C.

Thanks,

GyM

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