Problem Solving Pack 1, Question 1 At a company meeting, M men and

Question

QUANT 4-PACK SERIES Problem Solving Pack 1 Question 1 At a company meeting...

At a company meeting, M men and W women meet in a conference room. If there are twice as many men as women at the meeting and the conference room can hold no more than 50 total people, then what is the maximum number of women who can be at that meeting?

A) 15
B) 16
C) 17
D) 18
E) 19

A) 15
B) 16
C) 17
D) 18
E) 19

48 Hour Window Answer & Explanation Window   
 Earn KUDOS!  Post your answer and explanation.
OA, and explanation will be posted after the 48 hour window closes.

This question is part of the Quant 4-Pack series

Scroll Down For Official Explanation

camlan1990 · Answer

M+W <=50, M=2W => 3W <=50 => W<=16 Ans: B

ENGRTOMBA2018 · Answer

As per the given information, M=2W and M+W  \leq 50

Thus, 2W+W  \leq 50 ---> 3W  \leq  50 ---> W  \leq 16.67 ---> Max (W) = 16. B is the correct answer.

EMPOWERgmatRichC · Answer

Hi All,

This question can be approached Algebraically or by TESTing THE ANSWERS. Since there are already some Algebra-based explanations in this thread, here is how you can get to the solution by TESTing THE ANSWERS.

We're given a couple of facts to work with:
1) There are TWICE as men as women in a conference room
2) The conference room can hold UP TO 50 people.

We're asked for the MAXIMUM number of WOMEN that the room can hold.

Let's TEST Answer D: 18 women
IF... there were 18 women, then there would be 2(18) = 36 men.
18 + 36 = 54, but that is TOO MANY people (the room can only hold up to 50), so this answer is TOO BIG.
Eliminate D and E (that answer would be even BIGGER).

Answer C: 17 women
IF... there were 17 women, then there would be 2(17) = 34 men.
17 + 34 = 51, but that is TOO MANY people (although it's REALLY close), so this answer is TOO BIG.
Eliminate C.

Answer B: 16 women
IF... there were 16 women, then there would be 2(16) = 32 men.
16 + 32 = 48. This is the LARGEST answer that 'fits' all of the information that we've been given, so this MUST be the answer.

Final Answer:  B

GMAT assassins aren't born, they're made
Rich

sanguine31 · Answer

M=2W
M+W \leq{50} 
=>3W \leq{50} 
=>W \leq{16.66}

We have to maximize the number of women. but W=17 not possible as M=2W and the maximum no. of people that can be accommodated=50.

Hence Max. W=16.

ScottTargetTestPrep · Answer

We are given that there are twice as many men as women at a meeting; thus M = 2W. If the room can hold no more than 50 people, we can create the following equation:

M + W ≤ 50

2W + W ≤ 50

3W ≤ 50

W ≤ 50/3 = 16 ⅔

Thus, the maximum number of women at the meeting is 16.

Answer: B

aryan440 · Answer

Using Ration Method M:W = 1:2 AS WE NEED TO KNOW THE MAX. NUMBER OF WOMEN ATQ, M+W = 50 W = 50/(1+2) = 16.67 = 16 (APP) SO ANSWER OPTION (B) HAPPY LEARNING

bumpbot · Answer

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.

Problem Solving Pack 1, Question 1 At a company meeting, M men and

Prep Toolkit

Top 5 GMAT Debrief Videos

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards

GMAT Problem Solving (PS) Questions

Problem Solving Pack 1, Question 1 At a company meeting, M men and

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards