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Re: confusing PS

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Intern
Joined: 08 Aug 2009
Posts: 19

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01 Dec 2009, 12:47
1
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Difficulty:

(N/A)

Question Stats:

67% (00:36) correct 33% (01:18) wrong based on 5 sessions

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In a certain sequence, the first term is 1, and each successive term is 1 more than the reciprocal of the term that immediately proceeds it. What is the fifth term of the sequence?

a) 3/5
b) 5/8
c) 8/5
d) 5/3
e) 9/2

Thanks

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Senior Manager
Joined: 30 Aug 2009
Posts: 275
Location: India
Concentration: General Management

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01 Dec 2009, 13:03
wolver123 wrote:
In a certain sequence, the first term is 1, and each successive term is 1 more than the reciprocal of the term that immediately proceeds it. What is the fifth term of the sequence?

a) 3/5
b) 5/8
c) 8/5
d) 5/3
e) 9/2

Thanks

is it proceeds?? guess it should be precede
if the q states that term 2 is sum of 1+ reciprocal of first term and so on, then we will get 8/5
Intern
Joined: 08 Aug 2009
Posts: 19

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01 Dec 2009, 13:10
I thought it was precede as well. Struggled and couldnt find the answer as the question states proceeds. OA is C
Intern
Joined: 17 Dec 2009
Posts: 41

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18 Dec 2009, 08:15
1st term = 1, 2nd term 1+2 = 2, 3rd term 1/2 + 1 = 3/2, 4th term 2/3+1=5/3, 5th term 3/5+1 = 8/5
Intern
Joined: 18 Dec 2009
Posts: 10

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18 Dec 2009, 20:20
1
Simple one!
the series is
1,2,3/2,5/3,8/5
Intern
Joined: 12 Oct 2009
Posts: 14

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19 Dec 2009, 08:09
Yes, this ones a walk through the park. Just don't forget to keep flipping the fraction (reciprocal). I almost did when I was calculating the 5th term. The answer is 8/5.

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06 Mar 2017, 03:29
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Re: Re: confusing PS &nbs [#permalink] 06 Mar 2017, 03:29
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