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Official Explanation

I. If one student is selected at random from the 75, the chance that the student will be older than 17 or on the Varsity team, or both is _________

To find the probability of choosing a student that is either older than 17, or on the Varsity team, or both can be written mathematically as follows.

P(> 17 n VT) + P(< 17 n VT)
=35 + 15
=50

To find the ratio divide the number found above by the total number of students.

\(\frac{50}{75}=\frac{2}{3}\)

In words this is 2 out of 3.

II. If one student is selected at random from the 75, the chance that the students is both younger than 17 and on the Varsity Soccer Team is_________

In mathematical terms this is written as the following,
P(VTn < 17)
=15

To find the ratio divide the number found above by the total number of students.

\(\frac{15}{75}=\frac{1}{5}\)

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For quest 1, I understood that we took 7 = older than 7 +(or) 3 = V team, But why didnt we add accounted for BOTH part of the question. I know there is some gap in my understanding, could anybody explain
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For quest 1, I understood that we took 7 = older than 7 +(or) 3 = V team, But why didnt we add accounted for BOTH part of the question. I know there is some gap in my understanding, could anybody explain


There are 15 stars, 7 are >17years and 3 are on varsity team but are <17 years.
Both are already accounted for in the 7 stars.

Actually, even if we had not mentioned, it would have given the answer.
The question is basically 'everyone>17(this will include varsity players and non-varsity player)' + 'varsity players<17'.
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5 students = 1 star
75 students = 15 stars


­I. If one student is selected at random from the 75, the chance that the student will be older than 17 or on the Varsity team, or both is [2 out of 3].

P (older than 17) + P (on Varsity Team) + P (both) = 1 - P (not on Varsity Team & younger than 17)

Those not on Varsity Team & younger than 17: the stars in grey circle only = 5 stars
=> P (not on Varsity Team & younger than 17) = \(\frac{5}{15} = \frac{1}{3}\)

P (older than 17) + P (on Varsity Team) + P (both) = \(1 - \frac{1}{3} = \frac{2}{3}\)


II. If one student is selected at random from the 75, the chance that the students is both younger than 17 and on the Varsity Soccer Team is [1 out of 5].

Younger than 17 & On Varsity team = 3 stars in the overlapping area

P = \(\frac{3}{15} = \frac{1}{5}\)­
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the student will be older than 17 or on the Varsity team, or both, I think this sentence is hard to understand and is easy to make misundeerstiang
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part 1 asks for the union of the three conditions
1-greater than 17=(total - less than 17)=75-40=35
2- team player which is 50
3- both greater than 17 and on team, which is nothing but (total - less than 17)=35 ;as n(none)=0 here
so using U=1 + 2 - 3=35+50-35=50
resulting in prob.=50/75=2/3
hope i am correct
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I am with you... not sure what the source of the question is but I have made some language edits. Hope I did not miss anything and hope it is easier now.

700999
the student will be older than 17 or on the Varsity team, or both, I think this sentence is hard to understand and is easy to make misundeerstiang
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