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dhruv96us
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S96-04 08 Nov 2021, 12:29
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I think this is a poor-quality question. Not proper English used.
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djagbaje
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GMAT 1: 710 Q47 V41
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S96-04 30 Jun 2022, 10:42
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Tried solving this question using the formula of the diagonal of a square (d)=Side(s)sqrt{2}, Meaning that r=s.sqrt{2}.

So the Side(s) = r/sqrt{2}.

but then i don't quite get the same answer
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BlueCrab
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S96-04 15 Aug 2022, 00:17
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This problem is time-taking but there’s a logical shortcut you can apply, after we get the diagram, one can notice that the majority part is in the first quadrant. Now putting pi = 3.1 and root2 = 1.4 in the options, the largest fraction will give you the answer.
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zico51
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GMAT 1: 660 Q44 V37
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S96-04 31 Aug 2022, 21:41
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Inputting numbers to get to the solution -

Consider the point A (d,d) = (2,2); the diameter is the length between origin and point A (2,2)

Center of circle = (1,1); radius = \sqrt{2}

Area of square inside the circle = 2 * 2 = 4

Area of circle = pi * r^2 = 2* pi

So, Area of the 4 leaves = area of circle - area of square = 2 pi - 4 ---> Area of the 2 leaves in Quadrant 1 = (2 pi - 4)/2 = (pi - 2)

Therefore,

Area of circle inside the first quadrant -

Area of square + Area of the 2 leaves

4 + (pi-2) = pi + 2

% area = pi + 2 / area of circle = (pi + 2)/ 2*pi. <-- Answer
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adamsbudad
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S96-04 07 Nov 2022, 23:19
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I found the area to be 2pi by substituting random numbers for d, and knowing that we are looking for percentage of the area I chose the answer with 2pi in the denominator.
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S96-04 08 Apr 2024, 00:20
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Hello from the GMAT Club BumpBot!

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