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dhruv96us
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GMAT 1: 710 Q47 V41
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BlueCrab
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Inputting numbers to get to the solution -

Consider the point A (d,d) = (2,2); the diameter is the length between origin and point A (2,2)

Center of circle = (1,1); radius = \sqrt{2}

Area of square inside the circle = 2 * 2 = 4

Area of circle = pi * r^2 = 2* pi

So, Area of the 4 leaves = area of circle - area of square = 2 pi - 4 ---> Area of the 2 leaves in Quadrant 1 = (2 pi - 4)/2 = (pi - 2)

Therefore,

Area of circle inside the first quadrant -

Area of square + Area of the 2 leaves

4 + (pi-2) = pi + 2

% area = pi + 2 / area of circle = (pi + 2)/ 2*pi. <-- Answer
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I found the area to be 2pi by substituting random numbers for d, and knowing that we are looking for percentage of the area I chose the answer with 2pi in the denominator.
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