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Bunuel
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amrit3982
Looking at the second condition of 1/x >1. it is imperative that x<1 for all x>0, So, I thought condition 2 will be sufficient....Dunno whether I am right? :roll: :roll: :roll:

The question asks whether x < 1, while 1/x > 0 means that x > 0. So, the second statement is not sufficient: if x = 1/2, then the answer will be YES but if x = 2, then the answer will be NO.
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Bunuel
Is \((x - 2)^2 \gt x^2\)?


(1) \(x^2 \gt x\)

(2) \(\frac{1}{x} \gt 0\)


Bunuel Can you walk me through a? This is what I'm doing.

x^2>X
X^2-X>0
x(X-1)>0
X>0 or X>1

How is it that these values are then "less than or greater than one?" I get it when I plug in numbers but I don't know where my algebra is going amiss. Why would we switch the direction of the > sign to be <0?
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Bunuel
Is \((x - 2)^2 \gt x^2\)?


(1) \(x^2 \gt x\)

(2) \(\frac{1}{x} \gt 0\)


Bunuel Can you walk me through a? This is what I'm doing.

x^2>X
X^2-X>0
x(X-1)>0
X>0 or X>1

How is it that these values are then "less than or greater than one?" I get it when I plug in numbers but I don't know where my algebra is going amiss. Why would we switch the direction of the > sign to be <0?

9. Inequalities



For more check Ultimate GMAT Quantitative Megathread



Hope it helps.
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Bunuel
Is \((x - 2)^2 \gt x^2\)?


(1) \(x^2 \gt x\)

(2) \(\frac{1}{x} \gt 0\)


Bunuel Can you walk me through a? This is what I'm doing.

x^2>X
X^2-X>0
x(X-1)>0
X>0 or X>1

How is it that these values are then "less than or greater than one?" I get it when I plug in numbers but I don't know where my algebra is going amiss. Why would we switch the direction of the > sign to be <0?

aaigla

You are right till the step x(x-1)>0. The correct implication of x(x-1)>0 is that x>1 or x<0. You're wrong to deduce that x>0. We can check this by taking a value between 0 and 1, for example, 0.5. At x=0.5, the expression x(x-1)>0 becomes 0.5(-0.5)>1, which is not true.

I hope you're clear now.
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if x^2>x
then x>1 right so we know that then why should we doo all these steps i think stat 1 is sufficent
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Bunuel
Is \((x - 2)^2 \gt x^2\)?


(1) \(x^2 \gt x\)

(2) \(\frac{1}{x} \gt 0\)

Wow, I just discovered this side of the GmatClub world and I'm amazed with the question pool. Curiosity aside, let's try to solve this:

Is \((x - 2)^2 \gt x^2\)?

\((x-2)^2 - x^2 \gt 0\)

\(-2(2x - 2) \gt 0\)

\(-4x + 4 \gt 0\)

Is \( x < 1\)?

1)\(x^2 - x > 0\)
x(x-1) > 0
Using wavy-curve:
x > 1 or x < 0 - Insufficient, as we have 2 different values for x
2)1/x > 0
This means that x is positive (x > 0)
Case1: x = 0.1
x < 1 -
Case2: x = 2
x > 1, Insufficient!
Combining (1) & (2):
x > 1 - Sufficient!
IMO, (C)!
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