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Set S and Set T both contain x elements. The average of Set S is 40.
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28 Jul 2017, 09:12
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Set S and Set T both contain x elements. The average of Set S is 40. If the average of Set S and Set T combined is 50, which of the following must be true? I. The average of Set T is 60. II. The range of Set T is greater than that of Set S. III. x is an even number (A) I only (B) I & II (C) II only (D) I & III (E) All of the above
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Re: Set S and Set T both contain x elements. The average of Set S is 40.
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28 Jul 2017, 09:32
Bunuel wrote: Set S and Set T both contain x elements. The average of Set S is 40. If the average of Set S and Set T combined is 50, which of the following must be true?
I. The average of Set T is 60.
II. The range of Set T is greater than that of Set S.
III. x is an even number
(A) I only
(B) I & II
(C) II only
(D) I & III
(E) All of the above Sum of all numbers of set S = \(40*x\) Sum of all numbers of set S & set T = \(50*2x\) (as both set S & set T contains \(x\) elements) Therefore sum of all elements of set T = \(100x  40x = 60x\) Hence average of set T = \(60x/x = 60\). Hence \(I\) must be true Suppose set S contain two elements {20,100}, then the average will be 40 but the range will be 120 and suppose set T contains two elements {60,60}, then the average will be 60 but the range will be 0. Hence \(II\) may or may not be true from the question stem we cannot say anything about \(x\) and to arrive at the average for set T we do not require the value of \(x\). Hence \(III\) may or may not be true Hence Option A



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Re: Set S and Set T both contain x elements. The average of Set S is 40.
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28 Jul 2017, 18:40
Bunuel wrote: Set S and Set T both contain x elements. The average of Set S is 40. If the average of Set S and Set T combined is 50, which of the following must be true?
I. The average of Set T is 60.
II. The range of Set T is greater than that of Set S.
III. x is an even number
(A) I only
(B) I & II
(C) II only
(D) I & III
(E) All of the above I. Average (S+T)= 100, Average S =40, Average T= 60.. MBT II. No idea of contents of sets; no idea of range...MNBT III. No idea of contents of sets nor value of x;...MNBT Answer: A



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Re: Set S and Set T both contain x elements. The average of Set S is 40.
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29 Jul 2017, 03:38
Bunuel wrote: Set S and Set T both contain x elements. The average of Set S is 40. If the average of Set S and Set T combined is 50, which of the following must be true?
I. The average of Set T is 60.
II. The range of Set T is greater than that of Set S.
III. x is an even number
(A) I only
(B) I & II
(C) II only
(D) I & III
(E) All of the above S & T both contains x elements. Av.(Set S) = 40 Sum (Set S) = 40x Av.(Set S & T) = 50 Sum (Set S & T) = 100x So Sum of Set T = 60x Av(Set T) = 60 I. CORRECT II. The Least and highest numbers in set S may be ( 30, 90) and Set T may be (60,60). SO we can't comment on the value of range. INCORRECT III. Since x has no role in finding the average values etc. So, we can't say x is even or not. INCORRECT Answer A
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Re: Set S and Set T both contain x elements. The average of Set S is 40.
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29 Jul 2017, 05:48
shashankism wrote: Bunuel wrote: Set S and Set T both contain x elements. The average of Set S is 40. If the average of Set S and Set T combined is 50, which of the following must be true?
I. The average of Set T is 60.
II. The range of Set T is greater than that of Set S.
III. x is an even number
(A) I only
(B) I & II
(C) II only
(D) I & III
(E) All of the above S & T both contains x elements. Av.(Set S) = 40 Sum (Set S) = 40x Av.(Set S & T) = 50 Sum (Set S & T) = 100x So Sum of Set T = 60x Av(Set T) = 60 I. CORRECT II. The Least and highest numbers in set S may be ( 30, 90) and Set T may be (60,60). SO we can't comment on the value of range. INCORRECT III. Since x has no role in finding the average values etc. So, we can't say x is even or not. INCORRECT Answer Ahi, just on a lighter side.. your signature says " Appreciate by clicking +1 kudos ( lets be generous, friends)" so instinctively thought of looking at your \(\frac{kudos.given}{kudos.recieved}\).. it is less than \(\frac{1}{2}\).. remembered a proverb  " Charity begins at home" :wink: On the lighter side. will remove it if offended
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Re: Set S and Set T both contain x elements. The average of Set S is 40.
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29 Jul 2017, 10:16
Bunuel wrote: Set S and Set T both contain x elements. The average of Set S is 40. If the average of Set S and Set T combined is 50, which of the following must be true?
I. The average of Set T is 60.
II. The range of Set T is greater than that of Set S.
III. x is an even number
(A) I only
(B) I & II
(C) II only
(D) I & III
(E) All of the above • Let the average be Set T be “T”.
o Average of S and T \(= \frac{(Tx + 40x)}{2x}\) o \(100 = T + 40\) o Thus, \(T = 60\) o Statement I is correct. • Let us now focus on the Range.
o Set S average is 40. o A possible scenario could be {40,40,40….x terms), the range is 0 in this case. o Set T average is 60. o A possible scenario could be {60, 60,60….x terms), the range is 0 in this case.
• Thus, we cannot say for sure if the range of Set T is greater than Set S. o Statement II is not always true. • Finally, we do not know the value of x, it could be even or odd. Thus, the correct answer is Option A.Thanks, Saquib Quant Expert eGMATRegister for our Free Session on Number Properties (held every 3rd week) to solve exciting 700+ Level Questions in a classroom environment under the realtime guidance of our Experts [url=https:// egmat.com/freetrialregistration/?utm_source=GC&utm_medium=post&utm_campaign=registration&utm_content=free_trial_registration&utm_term=wp_q1] [/url
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Re: Set S and Set T both contain x elements. The average of Set S is 40.
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29 Jul 2017, 20:11
chetan2u wrote: shashankism wrote: Bunuel wrote: Set S and Set T both contain x elements. The average of Set S is 40. If the average of Set S and Set T combined is 50, which of the following must be true?
I. The average of Set T is 60.
II. The range of Set T is greater than that of Set S.
III. x is an even number
(A) I only
(B) I & II
(C) II only
(D) I & III
(E) All of the above S & T both contains x elements. Av.(Set S) = 40 Sum (Set S) = 40x Av.(Set S & T) = 50 Sum (Set S & T) = 100x So Sum of Set T = 60x Av(Set T) = 60 I. CORRECT II. The Least and highest numbers in set S may be ( 30, 90) and Set T may be (60,60). SO we can't comment on the value of range. INCORRECT III. Since x has no role in finding the average values etc. So, we can't say x is even or not. INCORRECT Answer Ahi, just on a lighter side.. your signature says " Appreciate by clicking +1 kudos ( lets be generous, friends)" so instinctively thought of looking at your \(\frac{kudos.given}{kudos.recieved}\).. it is less than \(\frac{1}{2}\).. remembered a proverb  " Charity begins at home" :wink: On the lighter side. will remove it if offended Hahahaha... chetan2u Yes you are correct but presently I am continuously in Kudos collection mode and trying to provide solution of as many questions as possible. So if you can see I am working very hard to solve & provide better solution to quant questions which is my strong area. Meanwhile when I get a good solution I too provide kudos. Once I will start solving VA section, in which I am weaker than QA section, I will surely provide kudos to good answers. But for last 1 month I am just solving and providing solution.. Anyway your comments are always welcome, it will increase bond between us and will help gmatclub to be more interactive. Even my moto is to interact with as many nice people here as possible
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Re: Set S and Set T both contain x elements. The average of Set S is 40.
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29 Jul 2017, 23:51
Bunuel wrote: Set S and Set T both contain x elements. The average of Set S is 40. If the average of Set S and Set T combined is 50, which of the following must be true?
I. The average of Set T is 60.
II. The range of Set T is greater than that of Set S.
III. x is an even number
(A) I only
(B) I & II
(C) II only
(D) I & III
(E) All of the above Total of S = 40x Total of S & T combined = 100x (50*2x) Total of T = 60x Average in T = 60x/x = 60 I must be true Let x be odd S = 30,40,50 Range of S = 20 T = 60,60,60 Average of S & T combined = 50 Range of T = 0 II and III not necessarily be true Hence A
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Re: Set S and Set T both contain x elements. The average of Set S is 40.
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