Bunuel
Set S and Set T both contain x elements. The average of Set S is 40. If the average of Set S and Set T combined is 50, which of the following must be true?
I. The average of Set T is 60.
II. The range of Set T is greater than that of Set S.
III. x is an even number
(A) I only
(B) I & II
(C) II only
(D) I & III
(E) All of the above
Sum of all numbers of set S = \(40*x\)
Sum of all numbers of set S & set T = \(50*2x\) (as both set S & set T contains \(x\) elements)
Therefore sum of all elements of set T = \(100x - 40x = 60x\)
Hence average of set T = \(60x/x = 60\). Hence \(I\) must be true
Suppose set S contain two elements {-20,100}, then the average will be 40 but the range will be 120
and suppose set T contains two elements {60,60}, then the average will be 60 but the range will be 0. Hence \(II\) may or may not be true
from the question stem we cannot say anything about \(x\) and to arrive at the average for set T we do not require the value of \(x\). Hence \(III\) may or may not be true
Hence Option
A