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But why don't you multiply the \((y-5) \) by 3 as well?
I was doing this: \(3(x-5=\frac{2}{3}(y-5))\) \(3x-15=2(3y-15)\) \(3x-15=6y-30\) \(3x=6y-15\) \(x=2y-5\)
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Hi whollymoses,
Remember, when you multiply a number through an equation you can multiply each term JUST ONCE.
So, in this case, you should see that 2/3(y - 5) is just one term.
So when you multiply the entire equation by 3, we only need to multiply 2/3 by 3 and not the rest of the parenthesis. If you were to do that you’d be changing the value of the equation.
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Hi there,
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