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25 Apr 2025, 15:37
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IDs: 11
Max Cost: 7
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
70% (03:18) correct
30%
(03:54)
wrong
based on 115
sessions
History
Date
Time
Result
Not Attempted Yet
Six grocery items are labeled with ID numbers from 1 to 6: 1 – Apples; 2 – Bread; 3 – Carrots; 4 – Detergent; 5 – Eggs; 6 – Flour. Each item costs a distinct whole number of dollars between $2 and $7.
A shopper bought exactly three different items, spending exactly $14. They remember:
- They did not buy both Apples and Flour.
- If Bread were bought, then Eggs were also bought.
- Bread is the most expensive item.
- Carrots cost more than Detergent, which costs more than $2.
- Eggs cost $4.
Select for IDs the correct sum of the IDs of the items purchased, and for Max Cost the price of the most expensive item in the group in dollars.
A shopper bought exactly three different items, spending exactly $14. They remember:
- They did not buy both Apples and Flour.
- If Bread were bought, then Eggs were also bought.
- Bread is the most expensive item.
- Carrots cost more than Detergent, which costs more than $2.
- Eggs cost $4.
Select for IDs the correct sum of the IDs of the items purchased, and for Max Cost the price of the most expensive item in the group in dollars.
| IDs | Max Cost | |
| 6 | ||
| 7 | ||
| 9 | ||
| 11 | ||
| 12 | ||
| 13 |
ShowHide Answer
Official Answer
IDs: 11
Max Cost: 7
Updated on: 27 Apr 2025, 11:33
Originally posted by Kunal.lost on 26 Apr 2025, 04:12.
Last edited by Kunal.lost on 27 Apr 2025, 11:33, edited 2 times in total.
Last edited by Kunal.lost on 27 Apr 2025, 11:33, edited 2 times in total.
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Hi Bismuth83,
Just wanted to point out that the OA listed here is IDs:7 and Max Cost:11 whereas, after solving it I realized it should be the other way round (IDs: 11 and Max Cost:7)
Please confirm, and thanks for the question
Here's how I approached it:
Eggs cost $4 and Bread cost $7 (given)
Apples and Flour are out of the picture.
Carrots cost more than Detergent, which costs more than $2
So Detergent could either be $3 or $5 (choose numbers such that they're not taken by any other item and there is a possible number bigger than the chosen one that could be assigned to Carrots.)
Total amount spend = $14
Bread + Eggs ($7 + $4) = $11 ($3 left)
and the remaining $3 could only be assigned to Detergent.
Hence, the 3 items purchased were Bread, Eggs and Detergent. ($7 + $4 + $3 = $14)
Most expensive of the lot was Bread ($7)
And the total of their IDs would be: 2 (Bread) + 4 (Detergent) + 5 (Eggs) = 11.
Hence, 11 and 7.
Just wanted to point out that the OA listed here is IDs:7 and Max Cost:11 whereas, after solving it I realized it should be the other way round (IDs: 11 and Max Cost:7)
Please confirm, and thanks for the question
Here's how I approached it:
Eggs cost $4 and Bread cost $7 (given)
Apples and Flour are out of the picture.
Carrots cost more than Detergent, which costs more than $2
So Detergent could either be $3 or $5 (choose numbers such that they're not taken by any other item and there is a possible number bigger than the chosen one that could be assigned to Carrots.)
Total amount spend = $14
Bread + Eggs ($7 + $4) = $11 ($3 left)
and the remaining $3 could only be assigned to Detergent.
Hence, the 3 items purchased were Bread, Eggs and Detergent. ($7 + $4 + $3 = $14)
Most expensive of the lot was Bread ($7)
And the total of their IDs would be: 2 (Bread) + 4 (Detergent) + 5 (Eggs) = 11.
Hence, 11 and 7.
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26 Apr 2025, 04:25
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Solution:
Given in the question stem:
1. A shopper bought three different items for a total of $14. Eggs + Bread + Detergent = 4 + 7 + 3 = 14.
2. Each item costs a distinct whole number. of dollars between $2 and $7.
3. Apples and Flour are not bought.
4. If bread is bought, then Eggs are also bought.
5. Bread is the most expensive one.
6. Carrots cost more than detergent, which costs more than $2. Suppose Detergent is 3, then Carrot must be 5.
7. Eggs cost $4.
By looking at option 1. I am assuming that the sum of the IDs of the items purchased is Bread + Eggs + Detergent = 2 + 5 + 4= 11.
2. For Max Cost, the price of the most expensive item in the group in dollars should be Bread, which is 7.
So, the Sum of the IDs should be 11, and the expensive item among all is bread, which is 7.
Bismuth83, please provide your solution to this problem for more clarification. I think the answer to first is 11 and the second one should be 7.
Given in the question stem:
1. A shopper bought three different items for a total of $14. Eggs + Bread + Detergent = 4 + 7 + 3 = 14.
2. Each item costs a distinct whole number. of dollars between $2 and $7.
3. Apples and Flour are not bought.
4. If bread is bought, then Eggs are also bought.
5. Bread is the most expensive one.
6. Carrots cost more than detergent, which costs more than $2. Suppose Detergent is 3, then Carrot must be 5.
7. Eggs cost $4.
By looking at option 1. I am assuming that the sum of the IDs of the items purchased is Bread + Eggs + Detergent = 2 + 5 + 4= 11.
2. For Max Cost, the price of the most expensive item in the group in dollars should be Bread, which is 7.
So, the Sum of the IDs should be 11, and the expensive item among all is bread, which is 7.
Bismuth83, please provide your solution to this problem for more clarification. I think the answer to first is 11 and the second one should be 7.
Bismuth83
