It is currently 20 Mar 2018, 03:07

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Source GMATPrep

Author Message
Intern
Joined: 25 Dec 2008
Posts: 41

### Show Tags

12 Jan 2009, 06:24
1
This post was
BOOKMARKED
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If X not equal to –Y; is X-Y/X+Y>1
A. X>0
B. Y<0
Manager
Joined: 04 Jan 2009
Posts: 236

### Show Tags

12 Jan 2009, 10:50
shobuj40 wrote:
If X not equal to –Y; is X-Y/X+Y>1
A. X>0
B. Y<0

y!=x;

x>0
-y>0
if x<1,1/x>1, -y/x>-y
x-y/x+y>x-y+y>x (but could be still <1)
if x>1, 1/x<1-y/x<-y
x-y/x+y<x

both insufficient.
_________________

-----------------------
tusharvk

Intern
Joined: 25 Dec 2008
Posts: 41

### Show Tags

13 Jan 2009, 04:20
can't we do some simple equation in this case

X-Y/X+Y>1

so,
X-Y>X+Y
X-X>Y+Y
0>2Y
Y<0

can't we do this in this situation
WHY?
Manager
Joined: 04 Jan 2009
Posts: 236

### Show Tags

13 Jan 2009, 09:56
shobuj40 wrote:
can't we do some simple equation in this case

X-Y/X+Y>1

so,
X-Y>X+Y
X-X>Y+Y
0>2Y
Y<0

can't we do this in this situation
WHY?

OK. I have seen this question before. In that case we need
(x-y)/(x+y)>1 in the question stem.
_________________

-----------------------
tusharvk

Re: Source GMATPrep   [#permalink] 13 Jan 2009, 09:56
Display posts from previous: Sort by

# Source GMATPrep

Moderator: chetan2u

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.