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02 Jul 2020, 03:06
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
83% (00:42) correct
17%
(00:54)
wrong
based on 42
sessions
History
Date
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Not Attempted Yet
Square ABCD above has a side length of 4. BC is the diameter of the circle. Which of the following is the area of the shaded region?
A. \(16 − 5\pi\)
B. \(16 − 4\pi\)
C. \(16 − 3\pi\)
D. \(16 -2 \pi\)
E. \(16 - \pi\)
Attachment:
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02 Jul 2020, 03:15
Kudos
Bookmarks
Explanation:
Side of square = 2 x Radius of circle
r=4/2 =2
Required area = Area of Square - Area of Semicircle
= 16 - π(2)^2 / 2
= 16 - 2π
IMO-D
Side of square = 2 x Radius of circle
r=4/2 =2
Required area = Area of Square - Area of Semicircle
= 16 - π(2)^2 / 2
= 16 - 2π
IMO-D
02 Jul 2020, 03:17
Kudos
Bookmarks
Diameter CB is a side of the square ABCD.
\(CB = 4\)
\(Radius = \frac{CB}{2} = 2\)
Area of shaded region = Area of square - Area of semicircle
\(= 4^2 - \frac{\pi \times (radius)^2}{2}\)
\(= 16 - \frac{\pi \times (2)^2}{2}\)
\(= 16 - 2 \pi\)
OA, D
\(CB = 4\)
\(Radius = \frac{CB}{2} = 2\)
Area of shaded region = Area of square - Area of semicircle
\(= 4^2 - \frac{\pi \times (radius)^2}{2}\)
\(= 16 - \frac{\pi \times (2)^2}{2}\)
\(= 16 - 2 \pi\)
OA, D
Bunuel
