Last visit was: 31 Aug 2026, 15:43 It is currently 31 Aug 2026, 15:43
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
User avatar
keiraria
User avatar
Joined: 05 Apr 2012
Last visit: 01 May 2017
Posts: 29
Own Kudos:
216
Given Kudos: 12
Posts: 29
Kudos: 216
SQUARE ROOTS 11 Apr 2017, 05:42
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello
can anyone help me to work with the following exercises

( \sqrt{}6+2) (\sqrt{}3-2)
THANKS


Best Regards

Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
User avatar
broall
User avatar
Retired Moderator
Joined: 10 Oct 2016
Last visit: 07 Apr 2021
Posts: 1,131
Own Kudos:
7,546
Given Kudos: 65
Status:Long way to go!
Location: Viet Nam
Posts: 1,131
Kudos: 7,546
SQUARE ROOTS 11 Apr 2017, 06:52
Kudos
Add Kudos
Bookmarks
Bookmark this Post
keiraria
Hello
can anyone help me to work with the following exercises

( \sqrt{}6+2) (\sqrt{}3-2)
THANKS


Best Regards
Show more

You mean \((\sqrt{6}+2)(\sqrt{3} - 2)\) ?
avatar
laxpro2001
avatar
Joined: 30 Mar 2017
Last visit: 28 Sep 2018
Posts: 29
Own Kudos:
28
Given Kudos: 47
Location: United States (FL)
Posts: 29
Kudos: 28
SQUARE ROOTS 11 Apr 2017, 14:11
Kudos
Add Kudos
Bookmarks
Bookmark this Post
nguyendinhtuong
keiraria
Hello
can anyone help me to work with the following exercises

( \sqrt{}6+2) (\sqrt{}3-2)
THANKS


Best Regards

You mean \((\sqrt{6}+2)(\sqrt{3} - 2)\) ?
Show more


I assume you meant to put what nguyendinhtuong wrote in his reply. In this case, you would FOIL the 2 expressions:
\(\sqrt{18} - 2\sqrt{6} + 2\sqrt{3} - 4\)
\(\sqrt{18}\) can be re-written as \(\sqrt{9}*\sqrt{2}\)which reduces to \(3\sqrt{2}\)

Is this what you were looking for?
User avatar
keiraria
User avatar
Joined: 05 Apr 2012
Last visit: 01 May 2017
Posts: 29
Own Kudos:
216
Given Kudos: 12
Posts: 29
Kudos: 216
SQUARE ROOTS 11 Apr 2017, 14:46
Kudos
Add Kudos
Bookmarks
Bookmark this Post
nguyendinhtuong
keiraria
Hello
can anyone help me to work with the following exercises

( \sqrt{}6+2) (\sqrt{}3-2)
THANKS


Best Regards

You mean \((\sqrt{6}+2)(\sqrt{3} - 2)\) ?
Show more
YES :) THANKS AND HOW TO PROCEED THE REST THE OA IS SQUARE ROOT OF 2

I Have done 3 square root of 2 then I have put -2 square root of 3 time square root of 2 and +2 square root of 3 and- 4 ?
User avatar
keiraria
User avatar
Joined: 05 Apr 2012
Last visit: 01 May 2017
Posts: 29
Own Kudos:
216
Given Kudos: 12
Posts: 29
Kudos: 216
SQUARE ROOTS 11 Apr 2017, 14:47
Kudos
Add Kudos
Bookmarks
Bookmark this Post
nguyendinhtuong
keiraria
Hello
can anyone help me to work with the following exercises

( \sqrt{}6+2) (\sqrt{}3-2)
THANKS


Best Regards

You mean \((\sqrt{6}+2)(\sqrt{3} - 2)\) ?
Show more
YES :) THANKS AND HOW TO PROCEED THE REST THE OA IS SQUARE ROOT OF 2

I Have done 3 square root of 2 then I have put -2 square root of 3 time square root of 2 and +2 square root of 3 and- 4 ?
User avatar
broall
User avatar
Retired Moderator
Joined: 10 Oct 2016
Last visit: 07 Apr 2021
Posts: 1,131
Own Kudos:
7,546
Given Kudos: 65
Status:Long way to go!
Location: Viet Nam
Posts: 1,131
Kudos: 7,546
SQUARE ROOTS 11 Apr 2017, 18:09
Kudos
Add Kudos
Bookmarks
Bookmark this Post
keiraria
nguyendinhtuong
keiraria
Hello
can anyone help me to work with the following exercises

( \sqrt{}6+2) (\sqrt{}3-2)
THANKS


Best Regards

You mean \((\sqrt{6}+2)(\sqrt{3} - 2)\) ?
YES :) THANKS AND HOW TO PROCEED THE REST THE OA IS SQUARE ROOT OF 2

I Have done 3 square root of 2 then I have put -2 square root of 3 time square root of 2 and +2 square root of 3 and- 4 ?
Show more

Sorry, but I can't get your point. Can you elaborate more?
User avatar
ccooley
User avatar
Manhattan Prep Instructor
Joined: 04 Dec 2015
Last visit: 06 Jun 2020
Posts: 931
Own Kudos:
1,665
 [1]
Given Kudos: 115
GMAT 1: 790 Q51 V49
GRE 1: Q170 V170
Expert
Expert reply
GMAT 1: 790 Q51 V49
GRE 1: Q170 V170
Posts: 931
Kudos: 1,665
 [1]
SQUARE ROOTS 12 Apr 2017, 12:04
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I think there's a mistake either with the OA (sqrt(2)), or with the phrasing of the question. As it stands, the answer to this one can't be sqrt(2). Among other issues, the answer to your question will be a negative number, since sqrt(3) < 2. So, sqrt(3) - 2 will be negative. Since it's being multiplied by a positive value, the result will be negative.
User avatar
keiraria
User avatar
Joined: 05 Apr 2012
Last visit: 01 May 2017
Posts: 29
Own Kudos:
216
Given Kudos: 12
Posts: 29
Kudos: 216
SQUARE ROOTS 14 Apr 2017, 01:05
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ccooley
I think there's a mistake either with the OA (sqrt(2)), or with the phrasing of the question. As it stands, the answer to this one can't be sqrt(2). Among other issues, the answer to your question will be a negative number, since sqrt(3) < 2. So, sqrt(3) - 2 will be negative. Since it's being multiplied by a positive value, the result will be negative.
Show more
ccooley
I think there's a mistake either with the OA (sqrt(2)), or with the phrasing of the question. As it stands, the answer to this one can't be sqrt(2). Among other issues, the answer to your question will be a negative number, since sqrt(3) < 2. So, sqrt(3) - 2 will be negative. Since it's being multiplied by a positive value, the result will be negative.
Show more

hello
thanks for your answer and feedback, from the beginning this simple exercise has something wrong
I have included my approach as attachment
thanks
Attachments

File comment: my approach
IMG_3709.JPG
IMG_3709.JPG [ 1.62 MiB | Viewed 3011 times ]

User avatar
broall
User avatar
Retired Moderator
Joined: 10 Oct 2016
Last visit: 07 Apr 2021
Posts: 1,131
Own Kudos:
7,546
Given Kudos: 65
Status:Long way to go!
Location: Viet Nam
Posts: 1,131
Kudos: 7,546
SQUARE ROOTS 14 Apr 2017, 06:41
Kudos
Add Kudos
Bookmarks
Bookmark this Post
OMG, could you post another better image? I cant read anything
User avatar
keiraria
User avatar
Joined: 05 Apr 2012
Last visit: 01 May 2017
Posts: 29
Own Kudos:
216
Given Kudos: 12
Posts: 29
Kudos: 216
SQUARE ROOTS 19 Apr 2017, 14:00
Kudos
Add Kudos
Bookmarks
Bookmark this Post
nguyendinhtuong
OMG, could you post another better image? I cant read anything
Show more
HELLO
PLEASE FIND ATTACHED A BETTER IMAGE

THANKS

BEST REGARDS
Attachments

File comment: MY APPROACH
IMG_3711 (2).JPG
IMG_3711 (2).JPG [ 1.52 MiB | Viewed 2900 times ]

User avatar
broall
User avatar
Retired Moderator
Joined: 10 Oct 2016
Last visit: 07 Apr 2021
Posts: 1,131
Own Kudos:
7,546
Given Kudos: 65
Status:Long way to go!
Location: Viet Nam
Posts: 1,131
Kudos: 7,546
SQUARE ROOTS 20 Apr 2017, 01:16
Kudos
Add Kudos
Bookmarks
Bookmark this Post
keiraria

HELLO
PLEASE FIND ATTACHED A BETTER IMAGE

THANKS

BEST REGARDS
Show more

The OA is totally wrong.

\(\sqrt{18}-2\sqrt{6}+2\sqrt{3}-4 \\
= \sqrt{9 \times 2} + 2\sqrt{3} - 2\sqrt{3} \times \sqrt{2} - 4 \\
\neq \sqrt{9 \times 2} + (2\sqrt{3} - 2\sqrt{3}) - 4 \sqrt{2}\)

Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!