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Square RSTU shown above is rotated in a plane about its center in a

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Joined: 28 Jun 2011
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Square RSTU shown above is rotated in a plane about its center in a [#permalink]

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New post 08 Aug 2011, 17:36
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Square RSTU shown above is rotated in a plane about its center in a clockwise direction the minimum number of degrees necessary for T to be in the position where S is now shown. The number of degrees through which RSTU is rotated is

(A) 135 degree
(B) 180 degree
(C) 225 degree
(D) 270 degree
(E) 315 degree

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[Reveal] Spoiler: OA
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Re: Square RSTU shown above is rotated in a plane about its center in a [#permalink]

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New post 09 Aug 2011, 03:36
WILLBEATGMAT2011 wrote:
Square RSTU shown above is rotated in a plane about its center in a clockwise direction the minimum number of degrees necessary for T to be in the position where S is now shown. The number of degrees through which RSTU is rotated is

(A) 135 degree
(B) 180 degree
(C) 225 degree
(D) 270 degree
(E) 315 degree


Attachment:
Ques3.jpg
Ques3.jpg [ 6.47 KiB | Viewed 2407 times ]

From the options, I am assuming the positioning of S and T relative to each other to be as shown. To replace S by T, focus on OT. Say, you rotate OT clockwise (and with it the entire square) and bring it in place of OS. How many degrees did you go? You covered 3 right angles i.e. 270 degrees.
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Re: Square RSTU shown above is rotated in a plane about its center in a [#permalink]

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New post 16 Sep 2017, 23:40
Here if we conenct 2 diagonals we get center of square O.
Now assume O as center and T on circumference we are drawing a circle in clockwise direction.
So now to reach S from T => we moved from OT to OU to OR to OS
As diagonals intersect at 90 degree => OT to OU =90 then OU to OR =90 degree then OR to OS =90 degree rotation.
Total = 270 degrees

Answer: D
Re: Square RSTU shown above is rotated in a plane about its center in a   [#permalink] 16 Sep 2017, 23:40
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Square RSTU shown above is rotated in a plane about its center in a

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