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18 Jun 2016, 07:10
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
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Question Stats:
89% (01:03) correct
11%
(01:47)
wrong
based on 742
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Starting from point O on a flat school playground, a child walks 10 yards due north, then 6 yards due east, and then 2 yards due south, arriving at point P. How far apart, in yards, are points O and P?
(A) 18
(B) 16
(C) 14
(D) 12
(E) 10
(A) 18
(B) 16
(C) 14
(D) 12
(E) 10
Let point O be the origin.
moving 10 yards due north = (0,10).
moving 6 yards due east = (6,10).
moving 2 yards due south = (6,8) =Final point P.
The distance from origin O(0,0) to point P(6,8) = 10.
Even though I did it in this way, the best way is to not use the coordinates.
moving 10 yards due north = (0,10).
moving 6 yards due east = (6,10).
moving 2 yards due south = (6,8) =Final point P.
The distance from origin O(0,0) to point P(6,8) = 10.
Even though I did it in this way, the best way is to not use the coordinates.
18 Jun 2016, 07:39
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bimalr9
Work on the movement in east-west and north south Direction as all moves will be at 90 degree and finally we will have a Right angle triangle..
N-S = 10 UP and 2 down = 10-2 = 8....
E-W = 6..
HYP = \(\sqrt{8^2+6^2}=\sqrt{64+36}=\sqrt{100}=10\)
E
19 Jun 2016, 07:59
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bimalr9
Attachment:
Distance.png [ 3.29 KiB | Viewed 17410 times ]
Distance OP = \(\sqrt{8^2 + 6^2}\) =>10
Hence answer will be (E) 10
