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\(\frac{40+100+x}{3} - \frac{110+30+85}{3}=10\)

\(140+x-140-85=30\)

\(x=115\)

Answer is (B)
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\(\frac{40+100+x}{3}\) - \(\frac{110+30+85}{3}\) = 10

\(\frac{140 +x}{3}\)- \(\frac{140 +85}{3}\) = 10

So, x - 85 = 30
x = 115

So, option B.
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Bunuel
The average (arithmetic mean) of 110, 30, and 85 is 10 less than the average of 40, 100, and

A. 110
B. 115
C. 120
D. 125
E. 130

Video Explanation



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