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17 Feb 2020, 08:28
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D
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Difficulty:
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Question Stats:
61% (01:32) correct
39%
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wrong
based on 130
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The average of the five members is 7. If one of the members is multiplied by 3, the average of the numbers increases to 9.4. Which of the five numbers is multiplied by 3?
A. 4
B. 5
C. 5.6
D. 6
E. None of these
A. 4
B. 5
C. 5.6
D. 6
E. None of these
Updated on: 18 Feb 2020, 02:58
Originally posted by Archit3110 on 17 Feb 2020, 11:55.
Last edited by Archit3110 on 18 Feb 2020, 02:58, edited 1 time in total.
Last edited by Archit3110 on 18 Feb 2020, 02:58, edited 1 time in total.
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Bunuel
The average of the five members is 7. If one of the members is multiplied by 3, the average of the numbers increases to 9.4. Which of the five numbers is multiplied by 3?
A. 4
B. 5
C. 5.6
D. 6
E. None of these
A. 4
B. 5
C. 5.6
D. 6
E. None of these
total sum ; 5*7 ; 35
now multiied by 3 ; 9.4 ; sum ; 47
∆ ; 12
if we subtract 2 cases ; 3a+b+c+d+e - (a+b+c+d+e) ; 2a = 12
a= 6
IMO D
mehro023
Current Student
GMAT 5: 730 Q50 V40
Posts: 55
17 Feb 2020, 12:38
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Let the 5 numbers be a,b,c,d,e
sum(a,b,c,d,e) = 5*7 = 35 = a + b + c + d + e ......(i)
Question states that one of the numbers is multiplied by 3, the average is 9.4
let a be the number multiplied by 3
so we have, sum(3a, b, c, d, e) = 5*9.4 = 47 = 3a + b + c + d + e ....(ii)
(ii) - (i)
2a = 12
a = 6
Thus, D
sum(a,b,c,d,e) = 5*7 = 35 = a + b + c + d + e ......(i)
Question states that one of the numbers is multiplied by 3, the average is 9.4
let a be the number multiplied by 3
so we have, sum(3a, b, c, d, e) = 5*9.4 = 47 = 3a + b + c + d + e ....(ii)
(ii) - (i)
2a = 12
a = 6
Thus, D
