rxs0005 wrote:
The botanic garden is planting bulbs for the spring flower show. The head gardener is trying to decide how to place three Tulips bulbs, three Daffodil bulbs, and three Crocus bulbs along the front row. How many different arrangements can he make of these bulbs in the front row?
(A) 27
(B) 108
(C) 216
(D) 512
(E) 1,680
Since we are not told otherwise, we can assume the three tulips, three daffodils, and crocuses are identical. Thus, the total number of arrangments is:
9!/(3! x 3! x 3!) = (9 x 8 x 7 x 6 x 5 x 4)/(3 x 2 x 3 x 2) = 8 x 7 x 6 x 5 = 1,680
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