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# The contents of a certain box consist of 14 apples and 23 or

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Senior Manager
Joined: 18 Oct 2010
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The contents of a certain box consist of 14 apples and 23 or  [#permalink]

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Updated on: 29 Sep 2012, 00:33
1
14
00:00

Difficulty:

25% (medium)

Question Stats:

77% (01:41) correct 23% (02:10) wrong based on 499 sessions

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The contents of a certain box consist of 14 apples and 23 oranges. How many oranges must be removed from the box so that 70 percent of the pieces of fruit in the box will be apples?

A. 3
B. 6
C. 14
D. 17
E. 20

Originally posted by heygirl on 01 Mar 2011, 13:12.
Last edited by Bunuel on 29 Sep 2012, 00:33, edited 1 time in total.
Renamed the topic and edited the question.
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01 Mar 2011, 13:19
8
2
heygirl wrote:
The contents of a certain box consist of 14 apples and 23 oranges. How many oranges must be removed from the box so that 70 percent of the pieces of fruit in the box will be apples?
(a)3
(b)6
(c)14
(d)17
(e)20

Thanks

As only oranges must be removed then 14 apples which are now in the box must comprise 70% of total # of fruits after removal: 0.7*total=14 --> total=20, and as there are 37 fruits now 37-20=17 oranges must be removed.

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01 Mar 2011, 13:22
2
The objective here is that 70% of the fruit in the box should be apples.

Now, there are 14 apples at start and there is no talk of removing any apples, so number of apples should remain 14 and they should constitute 70% of total fruit, so total fruit = 14/0.7 = 20

So we should have 20-14 = 6 oranges.

Right now, there are 23 oranges, so to get to 6 oranges, we should remove 23 - 6 = 17 oranges.

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01 Mar 2011, 13:40
bunuel and beyondgmatscore, Thanks. i got it now.
Geez, I feel like a fool to not have understood this
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05 Apr 2011, 09:56
1
The content of a certain box consists of 14 apples and 23 oranges. How many oranges must be removed from the box so that 70 percent of the pieces of fruit in the box will be apples?

A. 3
B. 6
C. 14
D. 17
E. 20

x= orange to be removed
14=70%(37-x)
x= 17
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05 Apr 2011, 10:21
1
Let x denotes the total no of fruits.

No of Apples remain the same.
Hence
14/x * 100 = 70
Solving we get x = 20

Apples = 14 Oranges = 6
Therfore, no of oranges to be removed = 17

Ans : D
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05 Apr 2011, 18:08
1
0.7(37-x) = 14
=> x =17

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05 Apr 2011, 19:19
(14)/(37-x) = 7/10

=> x = 17

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05 Apr 2011, 23:58
$$\frac {14}{x}$$ = $$\frac{70}{100}$$

Gives you twenty total pieces of fruit. 14 are apples, so 6 are oranges. 23-6=17 oranges that have to be removed

So

Imo D

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The content of a certain box consists of 14 apples and 23 orange  [#permalink]

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28 Sep 2012, 21:26
14 apples and 23 oranges

70 percent of the pieces of fruit in the box will be apples

--> 70%(T) = 14
T = 20

remaining
20-14 = 6

so 23-6 = 17

main point here is the apples remain the same no matter vvhat
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Re: The contents of a certain box consist of 14 apples and 23 or  [#permalink]

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16 Dec 2017, 13:50
Ratio of apples to oranges is 7 to 3.
Since there are 14 apples there needs to be 6 oranges. 23-17=6 so 17 apples need to be removed.

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Re: The contents of a certain box consist of 14 apples and 23 or  [#permalink]

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05 Mar 2018, 21:39
The content of a certain box consists of 14 apples and 23 oranges. How many oranges must be removed from the box so that 70 percent of the pieces of fruit in the box will be apples?

A. 3
B. 6
C. 14
D. 17
E. 20

Testing ans choices
If D = 17 no of oranges to be removed means there are 6 oranges left and 14 apples left a total of 20 fruits. 14 = 70% of 20 therefore D Is the correct ans
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Re: The contents of a certain box consist of 14 apples and 23 or  [#permalink]

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31 Jan 2019, 12:11
1
I did it like below:

Total Apples/(Total Fruits - Oranges to be removed) = 70%

Now assume Oranges to be removed = x

14/(14+23-x) = 70/100
Further solving will give :
20=37-x
x= 17

Hence D

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Re: The contents of a certain box consist of 14 apples and 23 or  [#permalink]

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04 Sep 2019, 14:24
A very simple and innocent approach of this problem is sufficient to solve this under 50 seconds:

14 Apples, 23 Oranges for 1 Box --> 14A + 23O = 1B, and we need to subtract enough Oranges to have 30% of oranges and 70% of apples left.

We know that the initial 14 Apples won't move, and that 2/3-->66% of 21 is 14! Just by understanding this, we can approximate the subtraction of 16 oranges to complete the equivalence, and the nearest number to this is 17: Answer D, it's done!
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Re: The contents of a certain box consist of 14 apples and 23 or  [#permalink]

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09 Nov 2019, 13:06
The question stem tells us that we will not remove any apples and the desired end state is to have 70% of the box be apples.
As a result we know that:
.70(future total fruit)=14 apples
future total fruit = 20

This means future total fruit will be 14 apples and 6 oranges. Right now we have 23 oranges and we need to get to 6, which we can do by removing 17 oranges.

Ans D.
Re: The contents of a certain box consist of 14 apples and 23 or   [#permalink] 09 Nov 2019, 13:06
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