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angoae
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula \(C=\frac{100,000p}{100-p}\). According to this estimate, how much more would it cost to remove 90 percent of the pollutant from the pond that it would cost to remove 80 percent of the pollutant?
A. $500,000
B. $100,000
C. $50,000
D. $10,000
E. $5,000
Ps.
I've got a question regarding the technique used by the explanation, so if someone were kind enough to clarify it I'd appreciate it!! This was a question from the new Official Guide 2016.
A. $500,000
B. $100,000
C. $50,000
D. $10,000
E. $5,000
Ps.
I've got a question regarding the technique used by the explanation, so if someone were kind enough to clarify it I'd appreciate it!! This was a question from the new Official Guide 2016.
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angoae
Joined: 19 Apr 2015
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Concentration: Technology, Marketing
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GMAT 1: 540 Q38 V27
GMAT 2: 620 Q42 V32
GPA: 3.55
WE:Marketing (Manufacturing)
Schools: Mendoza '20 Georgia Tech '19 Madison '19 Boston U '19 (D) Tepper '19 Tippie '19 Carroll '19 (WL) Kelley '19 (WD) Simon '19 Krannert '20 Iowa State '19 (S) Katz '19 (WD) Leeds '19 (A)
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04 Sep 2015, 01:37
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So after looking at the explanation I saw my error was that I was using .9 for 90% instead of simply inputting 90 directly. I can't understand why I would use 90 instead of .9!!
To get 90% of 100,000 I would simply multiply by .9!! That makes more sense to me than simply multiplying 90 directly to it.
For more clarification the book shows me the correct way of doing this was :
\(\frac{100,000*90}{100-90}\)
why I'am supposed to do that! As opposed to what I was initially thinking.
To get 90% of 100,000 I would simply multiply by .9!! That makes more sense to me than simply multiplying 90 directly to it.
For more clarification the book shows me the correct way of doing this was :
\(\frac{100,000*90}{100-90}\)
why I'am supposed to do that! As opposed to what I was initially thinking.
04 Sep 2015, 01:54
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Bookmarks
angoae
So after looking at the explanation I saw my error was that I was using .9 for 90% instead of simply inputting 90 directly. I can't understand why I would use 90 instead of .9!!
To get 90% of 100,000 I would simply multiply by .9!! That makes more sense to me than simply multiplying 90 directly to it.
For more clarification the book shows me the correct way of doing this was :
\(\frac{100,000*90}{100-90}\)
why I'am supposed to do that! As opposed to what I was initially thinking.
To get 90% of 100,000 I would simply multiply by .9!! That makes more sense to me than simply multiplying 90 directly to it.
For more clarification the book shows me the correct way of doing this was :
\(\frac{100,000*90}{100-90}\)
why I'am supposed to do that! As opposed to what I was initially thinking.
The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula
if you pay close attention to the highlighted portion, you will realize that question asks about " p percent ". now if you put p = .9, then it becomes .9% , which is clearly not the intended percentage required to be calculated in the given question. i hope it helps.
