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Manager  Joined: 05 Jan 2011
Posts: 100
The cost of 3 chocolates, 5 biscuits, and 5 ice creams is  [#permalink]

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5
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29 00:00

Difficulty:   95% (hard)

Question Stats: 25% (02:46) correct 75% (02:30) wrong based on 814 sessions

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The cost of 3 chocolates, 5 biscuits, and 5 ice creams is 195. What is the cost of 7 chocolates, 11 biscuits and 9 ice creams?

(1) The cost of 5 chocolates, 7 biscuits and 3 ice creams is 217.
(2) The cost of 4 chocolates, 1 biscuit and 3 ice creams is 141.

Originally posted by Onell on 20 Mar 2011, 08:56.
Last edited by Bunuel on 12 Jul 2013, 10:40, edited 1 time in total.
Edited the OA.
Intern  Joined: 06 Feb 2011
Posts: 8
Re: The cost  [#permalink]

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16
5
Given: 3C + 5B + 5I = 195---------(a)
7C + 11B + 9I = ?-----------------(b)
So we need to look for 4C + 6B + 4I (b-a)

(1). 5C+ 7B + 3I = 217--------------(c)
(a)+(c) gives 8C + 12B + 8I = 412 which is equal to 4C + 6B + 4I = 206
Thus sufficient.

(2). 4C+1B+3I = 141
Not sufficient.

General Discussion
Manager  Joined: 14 Feb 2011
Posts: 144
Re: The cost  [#permalink]

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Onell wrote:
The cost of 3 chocolates, 5 biscuits, and 5 ice creams is 195. What is the cost of 7 chocolates, 11 biscuits and 9 ice creams?

(A) The cost of 5 chocolates, 7 biscuits and 3 ice creams is 217.
(B) The cost of 4 chocolates, 1 biscuit and 3 ice creams is 141.

We know that 3C+5B+5I = 195 ........ (1)

We need to find 7C+11B+9I = ? ........ (2)

Statement 1 tells us 5C+7B+3I = 217...... (3). Whatever we do with (1) and (3), we cant get to (2), so insufficient

Statement 2 tells us 4C+1B+3I = 141...... (4). Whatever we do with (1) and (4), we cant get to (2), so insufficient again

Combining the two statements, we have three unique equations and three variables, so we can solve for C, B and I and can find the required value in (2).

Director  Joined: 01 Feb 2011
Posts: 541
Re: The cost  [#permalink]

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Given 3C+5B+5I = 195

1. Not Sufficient

Not enough to derive the value of expression

2. Not Sufficient

Not enough to derive the value of expression

together, we got 3 different equations and we should be able to find C,B and I and hence enough to find out the asked expression value.
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Re: The cost  [#permalink]

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Given -> 3C + 5B + 5I = 195

7C + 11B + 9C = ?

From (1) 5C + 7B + 3I = 217, not sufficient

From (2) 4C + B + 3I = 141, not sufficient

But from(1) and (2), 3 variables and 3 different equations, so sufficient.

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Manager  Joined: 10 Nov 2010
Posts: 122
Re: The cost  [#permalink]

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nimisha wrote:
Given: 3C + 5B + 5I = 195---------(a)
7C + 11B + 9I = ?-----------------(b)
So we need to look for 4C + 6B + 4I (b-a)

(1). 5C+ 7B + 3I = 217--------------(c)
(a)+(c) gives 8C + 12B + 8I = 412 which is equal to 4C + 6B + 4I = 206
Thus sufficient.

(2). 4C+1B+3I = 141
Not sufficient.

Good catch nimisha.
Director  Status: Impossible is not a fact. It's an opinion. It's a dare. Impossible is nothing.
Affiliations: University of Chicago Booth School of Business
Joined: 03 Feb 2011
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Re: The cost  [#permalink]

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nimisha
I see a continuous pattern in GMAT questions and I had this intuition that this is a "lone wolf" - I mean one choice alone is sufficient. Which one I can't guess. So let me ask you - is addition / subtraction the only way to get around the coefficients or is there some other way?? Just add them and see if it works. If not subtract them and see if it works. Any other way??

nimisha wrote:
Given: 3C + 5B + 5I = 195---------(a)
7C + 11B + 9I = ?-----------------(b)
So we need to look for 4C + 6B + 4I (b-a)

(1). 5C+ 7B + 3I = 217--------------(c)
(a)+(c) gives 8C + 12B + 8I = 412 which is equal to 4C + 6B + 4I = 206
Thus sufficient.

(2). 4C+1B+3I = 141
Not sufficient.

Intern  Joined: 06 Feb 2011
Posts: 8
Re: The cost  [#permalink]

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2
Well, addition/subtraction plus some intuition can help to get down to the solution. while doing the math, we need to have some idea as to what might lead to the possible solution. In this one, we are given one equation and asked for the value for the second one, so here you would want to figure out the value for the difference one. With this knowledge you can start adding/subtracting... I dont know if there is a sure shot way to proceed for such questions (would defintly like to know if there is one)..
Manager  Joined: 07 Oct 2010
Posts: 134
Re: The cost  [#permalink]

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three variable, we will need 3 equations to solve the question , option A and B not similar to each other or with the given information.

Therefore answer = C
Manager  Joined: 04 Apr 2010
Posts: 117
Re: The cost  [#permalink]

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1
I am with Nimisha. If you are doing really well in GMAT and get this kind of questions, you should start cross-checking it with addition and subtraction.
The answer is A.
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The cost of 3 chocolates, 5 biscuits, and 5 ice creams is  [#permalink]

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4
My approach to this problem:

Given: 3c+ 5b+ 5i = 195(*)
We need to find: 7c+ 11b+ 5i = ?

(1) 5c + 7b + 3i = 217(**) ,
First, (*) - (**) => c+ b+ i = 11(#);
Second, (*) + (**) => 8c + 12b+ 8i = 412 (##);
Finally, (##) - (#) => 7c+ 11b+ 9i = 401

(2) - is obviously insufficient;

The correct answer is A

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Joined: 18 Aug 2017
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Re: The cost of 3 chocolates, 5 biscuits, and 5 ice creams is  [#permalink]

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just check whether the three are equations are linearly independent or not, by using row transformations on matrix
if LI= insufficient

if LD= sufficient Re: The cost of 3 chocolates, 5 biscuits, and 5 ice creams is   [#permalink] 27 Sep 2018, 11:01
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